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3 years ago

Need this done ASAP

Mathematics

1 answer:

ANEK [815]3 years ago

3 0

Answer:

The side length is 11 inches

Step-by-step explanation:

The volume of a cube is given by

V = s^3 where s is the side length

1331 in ^3 = s^3

Take the cube root of each side

(1331 in ^3 ) ^1/3 = s^3 ^ 1/3

11 in = s

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jonny [76]

Answer:

could it be as simple as x+1=y or y-1=x?

Step-by-step explanation:

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3 years ago

Write the equation in exponential form using the two points (0,1) and (1,3)

MakcuM [25]

Answer:

$y=3^x$

Step-by-step explanation:

The equation of the function in exponential form is

$y=a\cdot b^x$

The function is determined using points (0,1) and (1,3), so their coordinates satisfy the eduation. Substitute them:

$1=a\cdot b^0\Rightarrow a=1\ \ [b^0=1]\\ \\3=a\cdot b^1\Rightarrow 1\cdot b=3,\ b=3$

Thus, the equation of the function is

$y=3^x$

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3 years ago

im just wondering if any of you guys have school bc todays election day and their a bunch of questions

bagirrra123 [75]

Answer:

i do have school today

Step-by-step explanation:

hope you have a good day though :)

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3 years ago

Read 2 more answers

What is less than 5.8 in 6th grade math

Klio2033 [76]

Answer:

5.7 5.6 5.5 5.4 5.3 5.2 5.1 5 4.9 4.8 and so on.

Step-by-step explanation:

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3 years ago

Use the Rational Zeros Theorem to write a list of all possible rational zeros of the function.

marishachu [46]

Answer:

$\text{Possible rational zeros}=\pm1,\pm\frac{1}{2},\pm2,\pm3,\pm\frac{3}{2},\pm6,\pm9,\pm\frac{9}{2},\pm18$

Step-by-step explanation:

We have been given the function

$f(x)=-2x^2+4x^3+3x^2+18$

From the rational zeros theorem, we have

$\text{Possible rational zeros}=\pm\frac{\text{Factors of constant term}}{\text{Factors of leading coefficient}}$

From the given function,

Leading coefficient = 2

Factors of 2 are 1,2

Constant term = 18

Factors of constant term = 1, 2, 3, 6, 9, 18

Hence, we have

$\text{Possible rational zeros}=\pm\frac{1,2,3,6,9,18}{1,2}\\\\\text{Possible rational zeros}=\pm1,\pm\frac{1}{2},\pm2,\pm3,\pm\frac{3}{2},\pm6,\pm9,\pm\frac{9}{2},\pm18$

6 0

3 years ago