Question

Need help please!!!!!!!

Answer 1

Answer:

First Option {-2 , 0 , 2}

Step-by-step explanation:

A critical point occurs when the derivative is 0 or undefined.

The function in the question is undefined at x = 2 and at x = -2 because if we put x = 2 or x = -2 the denominator becomes 0 hence anything divided by 0 is undefined, and the derivative equals 0 at x = 0 so the critical points are

{-2 , 0 , 2}

Use the quotient rule to find the derivative of the function then equal it to zero

$y=\frac{x^2-1}{x^2-4}\\\\\frac{dy}{dx}=\frac{(x^2-4)(2x)-(x^2-1)(2x)}{(x^2-4)^2}\\\\0=\frac{(x^2-4)(2x)-(x^2-1)(2x)}{(x^2-4)^2}\\\\0=2x^3-8x-2x^3+2x\\0=-6x\\x=0$

Answer 2

I believe it’s the last one
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