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podryga [215]
2 years ago
15

In the year 2003, a company made $6.8 million in profit. For each consecutive year after that, their profit increased by 13%. Ho

w much would the company's profit be in the year 2006, to the nearest tenth of a million dollars?
Mathematics
1 answer:
LenKa [72]2 years ago
6 0

Answer:

$7.7 million

Step-by-step explanation:

Given: $6.8 million profit made by company.

           13% increase in profit every year.

Now, finding the company´s profit in the year of 2006.

As we know there is 13% increase in profit.

∴ Profit increase= \frac{13}{100} \times 6.8= \$ 0.884

Next adding company´s profit with increase in profit to get profit in the year 2006.

∴ 6.8+0.884= \$ 7.684 ≅ $7.7

The company´s profit in the year 2006 is $7.7 million.

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Annette [7]
Hello!

You need to separate this into two rectangles and add their areas together

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3 years ago
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oksano4ka [1.4K]

Answer:

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Step-by-step explanation:

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3 years ago
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Strike441 [17]
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y= 2((x-5)^2 - 25 + 49/2) = 2((x-5)^2 - 1/2) = 2(x-5)^2 - 1 

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Vertex = (q,r) = (5,-1)

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5 0
3 years ago
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NemiM [27]

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\boxed{2x-3}

Step-by-step explanation:

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3 years ago
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faust18 [17]

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D

Step-by-step explanation:

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