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raketka [301]
2 years ago
8

Total consumption of fruit juice in a particular country in 2006 was about 1.86 billion

Mathematics
1 answer:
hram777 [196]2 years ago
3 0

Answer:

Step-by-step explanation:

Kindly check explanation

Step-by-step explanation:

The population of that country in 2006 was 500 million. What was the average number of

gallons of fruit juice consumed per person in the country in 2006? Use pencil and paper. Using the per

person amount from this problem, about how many gallons would your class consume?

Total consumption in 2006 = 2.11 billion gallons (2,110,000,000)

Population of country in 2006 = 500,000,000

Average number of gallons of fruit juice consumed per person in the country in 2006:

Total consumption / total population

2,110,000,000 / 500,000,000

= 4.22 gallons per person

Number of gallons class will consume :

Assume number of students in class = 15

Hence, class consumption equals:

Average consumption per person × number of students in class :

4.22 × 15 = 63.3 gallons

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Lewis walked 9/10 of a mile. His friend walked 2/5 of the way with him. How many miles did Lewis's friend walk with him?
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Answer:

Lewis's friend walked with him 9/25 miles

Step-by-step explanation:

Given that

Lewis walked 9/10 of a mile

And His friend accompanied him on 2/5 of the way.

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A store is instructed by corporate headquarters to put a markup of 25​% on all items. An item costing ​$24 is displayed by the s
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Answer: The correct selling price is $29.97.

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Cost price of an item = $27

Mark up rate = 11%

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So, Amount after mark up would be

Hence, the correct selling price is $29.97.

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Drag and drop formal proof. Prove the Polygon Exterior Angle Sum Theorem for the enclosed triangle, that is ∠1+∠2+∠3=360°
jasenka [17]

Answer:

The sum of all the external angles of a triangle is 360°.

Step-by-step explanation:

Let there are n sides in a polygon.

So, there are n internal angles in the polygon, let ∠i1, ∠i2, ∠i3, ..., ∠in are the measure of n internal angles of the polygon.

The measure of external angle corresponding to ∠i1,  ∠1= 180°-∠i1,

The measure of external angle corresponding to ∠i2, ∠2 = 180°-∠i2,

Similarly, the measure of external angle corresponding to ∠in, ∠n = 180°-∠in.

Now, the sum of all the external angles of the polygon,

(∠1+∠2+...+∠n)=(180°-∠i1)+(180°-∠i2)+...+(180°-∠in)

=(180°+180°+...n times)-(∠i1+∠i2+...+∠in)

=n x 180° - (∠i1+∠i2+...+∠in)

As ∠i1+∠i2+...+∠in is the sum of all the internal angles of the polygon.

So, the sum of all the external angles of the polygon =

(n x 180°) - (sum of all the internal angles of the polygon).

In the case of a triangle, n=3  and the sum of all the three internal angles, ∠i1+∠i2+∠i3 = 180°.

Therefore, the sum of all the external angles of a triangle,

∠1+∠2+∠3 =3x180°-(∠i1+∠i2+∠i3)

                 =540°=180°

                 =360°.

Hence, the sum of all the external angles of a triangle is 360°.

5 0
3 years ago
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