No, a parallelogram is not a rectangle. meaning it has a completely different area formula, I know it sucks.
Formula: base × height
I don't use feet and inches. sorry I couldn't provide with to much help.
Y + 7 = 3x.....y = 3x - 7
6x - 2y = 12
6x - 2(3x - 7) = 12
6x - 6x + 14 = 12
14 = 12 (incorrect)
when ur variables cancel out and u r left with an incorrect statement, this means there is no solution because ur lines are parallel
so ur answer is : no solution
Answer:
A=24m^2
Step-by-step explanation:
to find the area of this figure you can approach it multiple ways, the simplest way is to split it into two rectangles
respectively one 6m by 3m and another 3m by 2m
find the areas of each rectangle and add them both to get the total area of the figure
(6m*3m)+(3m*2m)=(18+6)m^2=24m^2
Answer:From first time to second time
1:49
From second time to first time
-1:49
From first time to second time over midnight
25:49
From second time to first time over midnight
22:11
Step-by-step explanation:
Answer:
x = -1.14 or -13.14
Explanations:
The given equation is:
Find the half of 12, and add the square to both sides of the equation.
That is add 6² to both sides
Find the square root of both sides:
![\begin{gathered} \sqrt[]{(x+6)^2_{}}=\pm\sqrt[]{51} \\ \text{x + 6 = }\pm\sqrt[]{51} \\ x\text{ = -6 }\pm\sqrt[]{51} \\ \text{x = }-6\pm7.14 \\ x\text{ = -6+7.14 = }1.14 \\ x\text{ = -6 - 7.14} \\ \text{x = -13.14} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Csqrt%5B%5D%7B%28x%2B6%29%5E2_%7B%7D%7D%3D%5Cpm%5Csqrt%5B%5D%7B51%7D%20%5C%5C%20%5Ctext%7Bx%20%20%2B%20%206%20%20%3D%20%7D%5Cpm%5Csqrt%5B%5D%7B51%7D%20%5C%5C%20x%5Ctext%7B%20%20%3D%20%20-6%20%20%7D%5Cpm%5Csqrt%5B%5D%7B51%7D%20%5C%5C%20%5Ctext%7Bx%20%20%3D%20%7D-6%5Cpm7.14%20%5C%5C%20x%5Ctext%7B%20%20%3D%20-6%2B7.14%20%20%3D%20%7D1.14%20%5C%5C%20x%5Ctext%7B%20%3D%20-6%20-%207.14%7D%20%5C%5C%20%5Ctext%7Bx%20%3D%20-13.14%7D%20%5Cend%7Bgathered%7D)
x = -1.14 or -13.14
