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IrinaK [193]
4 years ago
5

Perform the specified operations on the polynomials: Subtract 2x2−3xy+4y2from 3x2−5xy−6y2

Mathematics
1 answer:
tankabanditka [31]4 years ago
8 0

Answer:

Solution to the given expression is (x^2 -10y^2 -2xy)

Step-by-step explanation:

Here, the given expression are:

P(x) = 2x^2- 3xy+4y^2\\Q(x) = 3x^2 - 5xy-6y^2

To Solve for : Q(x)  - P(x)

Now substitute the value of P(x) and Q(x) , we get:

Q(x) - P(x) = P(x) = (3x^2 - 5xy-6y^2) - (2x^2- 3xy+4y^2)\\= 3x^2 - 5xy-6y^2 - 2x^2+3xy-4y^2\\=x^2-10y^2-2xy\\\implies Q(x) - P(x) = (x^2-10y^2-2xy)

Hence solution to the given expression is (x^2 -10y^2 -2xy)

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A line is perpendicular to y = -1/5x+1
natta225 [31]

Answer:

y = 5\, x + 26.

Step-by-step explanation:

Start by finding the slope of the line perpendicular to y = (-1/5)\, x + 1.

The slope of y = (-1/5)\, x + 1 is (-1/5).

In a plane, if two lines are perpendicular to one another, the product of their slopes would be (-1).

Let m denote the slope of the line perpendicular to y = (-1/5)\, x + 1. The expression (-1/5)\, m would denote the product of the slopes of these two lines.

Since these two lines are perpendicular to one another, (-1/5)\, m = -1. Solve for m: m = 5.

The (-5,\, 1) is a point on the requested line. (That is, x_{1} = -5 and y_{1} = 1.) The slope of that line is found to be m = 5. The equation of that line in the point-slope form would be:

y - 1 = 5\, (x - (-5)).

Rewrite this point-slope form equation into the slope-intercept form:

y = 5\, x + 26.

5 0
3 years ago
What is the circumference of a circle with a 12cm diameter?
pochemuha

Answer:

37.7cm

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
At the first meeting of the Tennis Club, the 7 members decided to have a tournament in which every player will play a match agai
mariarad [96]

Answer:

21 matches

Step-by-step explanation:

This is a combination problem where we have to select two member out of 7 members

 

So we want calculation of  7C2

 

   7C2 = 7!/[(2!)(7-2)!]

   (7*6*5*4*3*2*1)/[(2*1) *(5*4*3*2*1]

   (7*6)/2    ~  Note everything that easily cancels here!

   42/2

   21 matches

5 0
3 years ago
I’m stuck and all the tuts are useless any help y’all?
Sidana [21]
Answer: 6n+1
Process: trial and error (sorry it’s not more i. depth)
6 0
2 years ago
The graph of linear function f passes through the point (1, -9) and has a slope of -3. What is the zero of f ?
den301095 [7]

Answer:

-2

Step-by-step explanation:

The standard equation of a line is y = mx+c

m is the slope

c is the intercept

Given

Slope = -3

Get the intercept c;

Substitute m = -3 and (1, -9) into y = mx+c

-9 = -3(1) + c

-9  = -3 + c

c = -9 + 3

c = -6

The equation becomes

y = -3x + (-6)

y = -3x-6

f(x) = -3x-6

The zero of f occurs at f(x) = 0

0 = -3x-6

3x = -6

x = -6/3

x = -2

Hence the zero of the function is -2

5 0
3 years ago
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