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IrinaK [193]
3 years ago
5

Perform the specified operations on the polynomials: Subtract 2x2−3xy+4y2from 3x2−5xy−6y2

Mathematics
1 answer:
tankabanditka [31]3 years ago
8 0

Answer:

Solution to the given expression is (x^2 -10y^2 -2xy)

Step-by-step explanation:

Here, the given expression are:

P(x) = 2x^2- 3xy+4y^2\\Q(x) = 3x^2 - 5xy-6y^2

To Solve for : Q(x)  - P(x)

Now substitute the value of P(x) and Q(x) , we get:

Q(x) - P(x) = P(x) = (3x^2 - 5xy-6y^2) - (2x^2- 3xy+4y^2)\\= 3x^2 - 5xy-6y^2 - 2x^2+3xy-4y^2\\=x^2-10y^2-2xy\\\implies Q(x) - P(x) = (x^2-10y^2-2xy)

Hence solution to the given expression is (x^2 -10y^2 -2xy)

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Choose whether it's always, sometimes, never 
Keith_Richards [23]

Answer: An integer added to an integer is an integer, this statement is always true. A polynomial subtracted from a polynomial is a polynomial, this statement is always true. A polynomial divided by a polynomial is a polynomial, this statement is sometimes true. A polynomial multiplied by a polynomial is a polynomial, this statement is always true.

Explanation:

1)

The closure property of integer states that the addition, subtraction and multiplication is integers is always an integer.

If a\in Z\text{ and }b\in Z, then a+b\in Z.

Therefore, an integer added to an integer is an integer, this statement is always true.

2)

A polynomial is in the form of,

p(x)=a_nx^n+a_{n-1}x^{x-1}+...+a_1x+a_0

Where a_n,a_{n-1},...,a_1,a_0 are constant coefficient.

When we subtract the two polynomial then the resultant is also a polynomial form.

Therefore, a polynomial subtracted from a polynomial is a polynomial, this statement is always true.

3)

If a polynomial divided by a polynomial  then it may or may not be a polynomial.

If the degree of numerator polynomial is higher than the degree of denominator polynomial then it may be a polynomial.

For example:

f(x)=x^2-2x+5x-10 \text{ and } g(x)=x-2

Then \frac{f(x)}{g(x)}=x^2+5, which a polynomial.

If the degree of numerator polynomial is less than the degree of denominator polynomial then it is a rational function.

For example:

f(x)=x^2-2x+5x-10 \text{ and } g(x)=x-2

Then \frac{g(x)}{f(x)}=\frac{1}{x^2+5}, which a not a polynomial.

Therefore, a polynomial divided by a polynomial is a polynomial, this statement is sometimes true.

4)

As we know a polynomial is in the form of,

p(x)=a_nx^n+a_{n-1}x^{x-1}+...+a_1x+a_0

Where a_n,a_{n-1},...,a_1,a_0 are constant coefficient.

When we multiply the two polynomial, the degree of the resultand function is addition of degree of both polyminals and the resultant is also a polynomial form.

Therefore, a polynomial subtracted from a polynomial is a polynomial, this statement is always true.

3 0
3 years ago
Read 2 more answers
Really need help! Brainliest to correct!
zlopas [31]

Answer:

<u>Given</u>:

  • R(x) = 59x - 0.3x²
  • C(x) = 3x + 14

<u>Find the following</u>:

  • P(x) = R(x) - C(x) = 59x - 0.3x² - 3x - 14 = -0.3x² + 56x - 14
  • R(80) = 59(80) - 0.3(80²) = 2800
  • C(80) = 3(80) + 14 = 254
  • P(80) = 2800 - 254 = 2546
7 0
3 years ago
Graph the system of equations. {x−y=64x+y=4
Fantom [35]
X-y=6 Equation 1
x+y=4 Equation 2

To graph the given system of equation, first find x and y-intercept of each equation.
x-y=6
When y=0
x=6  Point is (6,0)
When x=0
-y=6
y=-6  Point is (0,-6)

Now x-intercept and y-intercept for equation 2.
x+y=4
When x=0
y=4  Point is (0,4)
When y=0
x=4 Point is (4,0)

Now plot these points on the graph, the lines intersect each other at point (5,-1), which is the solution of the given system.

Answer: (5,-1)

5 0
3 years ago
In the figures below, the cube-shaped box is 6 inches wide and the rectangular box is 10 inches long, 4 inches wide, and 4 inche
olganol [36]
The cube-shaped box has a volume of 216 cubic inches. The rectangular box has a volume of 160 cubic inches. Therefore, the answer is C) 56 cubic inches.
7 0
3 years ago
5(x+2/3)=3x-2/3The answer is-2.Please show work so I can understand how to solve.
kramer
5(x + 2/3) = 3x - 2/3.....distribute the 5 through the parenthesis
5x + 10/3 = 3x - 2/3 ....subtract 3x from both sides
5x - 3x + 10/3 = 3x - 3x - 2/3...combine like terms
2x + 10/3 = - 2/3 ....subtract 10/3 from both sides
2x + 10/3 - 10/3 = -2/3 - 10/3...simplify
2x = - 12/3....reduce
2x = - 4....divide both sides by 2
x = -4/2....reduces to -2

or this way...
5(x + 2/3) = 3x - 2/3.....distribute
5x + 10/3 = 3x - 2/3....multiply by lowest common denominator of 3
15x + 10 = 9x - 2 ....subtract 9x from both sides
15x - 9x + 10 = -2 ...subtract 10 from both sides
6x + 10 - 10 = -2 - 10...simplify
6x = -12.....divide both sides by 6
x = -12/6 reduces to -2
6 0
3 years ago
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