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2 years ago

What is the equation of the line that passes through the point (2, -2) and has a slope of -1/2?

Mathematics

1 answer:

yanalaym [24]2 years ago

3 0

Answer:

Step-by-step explanation:

use the point-slope formula [y-y1 =m(x-x1) ] with the given info

for the point P=(x1,y1) =(2,-2) and the slople m = -1/2

plug those into the formula

y-(-2)= -1/2(x-2)

y+2= -1/2x + 1

y= -1/2x+1 - 2

y = -1/2x - 1

:) got it?

these are hard untill you get the idea of the two formulas

point-slope: y-y1 = m(x-x1) and

slope-intercept: y= mx+b

memorizing those will help a lot

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Answer:

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Step-by-step explanation:

3x - 5y = -3

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Please help me Determine the value of base b if (152)b = 0x6A. Please show all steps.

egoroff_w [7]

Answer:

The value of b is, 8

Step-by-step explanation:

To determine the value of b:

Given:

$(152)_b = 0x6A$ ....[1]

Since, 0x6A represents the hexadecimal form.

To convert this hexadecimal form into decimal form:

$(6A)_{16}= (6 \times 16^1)+(A \times 16^0)=(6 \times 16)+(10 \times 1) =96+10 = 106$

⇒ $0x6A=106$ (decimal form)

Now we have to convert this decimal form into octal

8 | 106

8 | 13 | 2

| 1 | 5

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Substitute this in [1] we have;

$(152)_b = (152)_8$

On comparing both sides we have;

b = 8

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Step-by-step explanation:

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