What is the equation of the line that passes through the point (2, -2) and has a slope of -1/2?
1 answer:
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Work backwards.
s=ut+(at^2)/2
Subtract ut.
s-ut=(at^2)/2
Multiply by 2.
2(s-ut)=at^2
Divide by a.
2(s-ut)/a=t^2
Find the square root:
s=ut+(at^2)/2
Subtract ut.
s-ut=(at^2)/2
Multiply by 2.
2(s-ut)=at^2
Divide by a.
2(s-ut)/a=t^2
Find the square root:
Answer:
Step-by-step explanation:
Given functions are:
We have to find:
(s.t)(x) => this means we have to multiply the two functions to get the result.
So,
Also we have to find
(s-t)(x) => we have to subtract function t from function s
Also we have to find,
(s+t)(-3) => first we have to find sum of both functions and then put -3 in place of x
Putting x = -3
Hence,