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nadya68 [22]
3 years ago
9

Which of the following graphs represents a function that has a positive

Mathematics
1 answer:
frutty [35]3 years ago
5 0

Answer:

you should try scanning that one instead of questioning here

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The product of a number and 9
Anna35 [415]

Answer:

9x

Step-by-step explanation:

let's say that x is the number we don't know

the product means multiplication

9*x=9x

so the answer is 9x

4 0
3 years ago
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What is the solution of each equation<br> 42=7f
olasank [31]

Answer:

f = 6

Step-by-step explanation:

f = 42/7 = 6

7 0
3 years ago
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Identify the slope and y-intercept of the<br> line!
marta [7]

Slope of the line = \frac{1}{2}.

y-intercept of the line = -7.

Solution:

General form of equation of a line:

y = mx + c

where m is the slope and c is the y-intercept of the line.

Equation of a line:

$y=\frac{1}{2} x-7

To compare this with general equation.

$m=\frac{1}{2}

c=-7

Slope of the line = \frac{1}{2}.

y-intercept of the line = -7.

5 0
3 years ago
Solve for y 16y^2-25=0
Pepsi [2]

Answer:

\large\boxed{x=-\dfrac{5}{4}\ \vee\ x=\dfrac{5}{4}}

Step-by-step explanation:

16y^2-25=0\\\\METHOD\ 1:\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\16=4^2\ \text{and}\ 25=5^2\ \text{therefore we have}\\\\4^2y^2-5^2=0\\\\(4y)^2-5^2=0\\\\(4y-5)(4y+5)+0\iff4y-5=0\ \vee\ 4y+5=0\\\\4y-5=0\qquad\text{add 5 to both sides}\\4y=5\qquad\text{divide both sides by 4}\\\boxed{y=\dfrac{5}{4}}\\\\4y+5=0\qquad\text{subtract 5 from both sides}\\4y=-5\qquad\text{divide both sides by 4}\\\boxed{x=-\dfrac{5}{4}}

METHOD\ 2:\\\\16y^2-25=0\qquad\text{add 25 to both sides}\\\\16y^2=25\qquad\text{divide both sides by 16}\\\\y^2=\dfrac{25}{16}\to y=\pm\sqrt{\dfrac{25}{26}}\\\\y=-\dfrac{\sqrt{25}}{\sqrt{16}}\ \vee\ x=\dfrac{\sqrt{25}}{\sqrt{16}}\\\\\boxed{y=-\dfrac{5}{4}\ \vee\ x=\dfrac{5}{4}}

7 0
3 years ago
Read 2 more answers
Is 7/8 or 11/10 closer to 1? How did you decide anybody help please?
erik [133]

Let

A-----> \frac{7}{8}

B-----> \frac{11}{10}

C-----> 1

we know that

Point A-------> Multiply numerator and denominator by 10

\frac{7*10}{8*10} =\frac{70}{80}

Point B-------> Multiply numerator and denominator by 8

\frac{11*8}{10*8} =\frac{88}{80}

Point C-------> Multiply numerator and denominator by 80

\frac{1*80}{1*80} =\frac{80}{80}

Find the distance Point A to Point C

\frac{80}{80} -\frac{70}{80} =\frac{10}{80}

Find the distance Point B to Point C

\frac{88}{80} -\frac{80}{80} =\frac{8}{80}

therefore

\frac{8}{80} < \frac{10}{80}

Point B is closer to Point C

\frac{11}{10} is closer to 1

the answer is

\frac{11}{10} is closer to 1

5 0
3 years ago
Read 2 more answers
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