Answer:
Step-by-step explanation:
Let's solve your system by substitution.
5x+3y=35;2x+4y=28
Step: Solve 5x+3y=35 for x:
5x+3y=35
5x+3y+−3y=35+−3y(Add -3y to both sides)
5x=−3y+35
5x/
5
=
−3y+35/
5 (Divide both sides by 5)
Step: Substitute −3/
5
y+7 for x in 2x+4y=28:
2x+4y=28
2(
−3/
5
y+7)+4y=28
14/
5
y+14=28 (Simplify both sides of the equation)
14/
5
y+14+−14=28+−14 (Add -14 to both sides)
14/
5
y=14
14/
5
y/
14/
5
=
14/
14/
5
(Divide both sides by 14/5)
y=5
Step: Substitute 5 for y in x=
−3/
5
y+7:
x=
−3/
5
y+7
x=
−3/
5
(5)+7
x=4 (Simplify both sides of the equation)
Answer:
x=4 and y=5
