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snow_lady [41]
3 years ago
12

Write an inequality for each sentence. More than 3400 people attended the tea market.

Mathematics
2 answers:
vladimir1956 [14]3 years ago
8 0
The answer would be

~X > 3400~

Hope this helps

Have a great day/night

Feel free to ask any questions
Alla [95]3 years ago
7 0

Answer:

the take video g g go ytffdee

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The square of the sum of a number and 11
shepuryov [24]

Answer:

(n+11)^2

Step-by-step explanation:

Hope this helps!

3 0
3 years ago
What is 594 divided by 24
kaheart [24]
594 ÷ 24 = 24.75 or 24\frac{3}{4}
4 0
3 years ago
Read 2 more answers
Given that the area of a trapezoid is given by the formula A = 1/ 2 h(b1 + b2), what is the value of A if h = 2 cm, b1 = 3, and
Wewaii [24]

Answer:

A=7

Step-by-step explanation:

A=1/2h(b1+b2)

plug in what you know

A=1/2x2(3+4)

PEMDAS

A=1/2x2(7)

A=1/2x14

A=7

8 0
4 years ago
A student would like to find the height of a statue. The length of the​ statue's right arm is 54 feet. The​ student's right arm
Komok [63]

Answer:


a) Approximate height of the statue: 144 feet

b) The approximate height is 1.7% greater that the actual height of the statue.


Explanation


1) Assume that the measures of the statue are proportional to the dimensions of the student. That means:


        statue's height                                   student's height

________________________   =    ______________________

length of the​ statue's right arm          length of student's right arm


⇒ x / 54 feet = (5 + 1/3) feet / 2 feet


⇒ x = 54 × (16/3) / 2 feet = (54×16) / (3×2) feet = 144 feet


Answer: 144 feet


2) Compare the approximate heigth obtained with the actual height:


144 feet - (143 feet + 9 inches) = 144 feet - (143 feet + 9/12 feet) = 1 feet - 9/12 feet


1 feet - 9/12 feet = 1 feet - 3/4 feet = 1/4 feet.


Hence, the approximate feet obtained is 1/4 feet larger than the actual height.


In relative terms that is : (1/4) / (143 + 3/4) = 0.0017 = 1.7%.

4 0
3 years ago
Find an equation of the tangent line to the curve 2(x2+y2)2=25(x2−y2) (a lemniscate) at the point (−3,1). An equation of the tan
valina [46]

2(x^2+y^2)^2=25(x^2-y^2)

Let y=y(x), so that differentiating both sides wrt x gives

4(x^2+y^2)\left(2x+2y\dfrac{\mathrm dy}{\mathrm dx}\right)=25\left(2x-2y\dfrac{\mathrm dy}{\mathrm dx}\right)

If x=-3 and y=1, the above reduces to

40\left(-6+2\dfrac{\mathrm dy}{\mathrm dx}\right)=25\left(-6-2\dfrac{\mathrm dy}{\mathrm dx}\right)\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac9{13}

This is the slope of the tangent line, which has equation

y-1=\dfrac9{13}(x+3)\implies\boxed{y=\dfrac{9x+40}{13}}

7 0
3 years ago
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