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3 years ago

If (x)=2x+10,then f^-1(x)

1 answer:

8 0

If f(x) = 2x + 10, then x = 2(f^-1(x)) + 10
[swap f(x) for x and x for f^-1(x)]

Rearrange:
2(f^-1(x)) = x - 10
f^-1(x) = (x - 10)/2

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The equation is;

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3 years ago

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Answer:

Given that:

$a = (\frac{x+ip}{2})^{\frac{1}{2}}$ and $a+= (\frac{x-ip}{2})^{\frac{1}{2}}$

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First find:

$aa^+ = (\frac{x+ip}{2})^{\frac{1}{2}} (\frac{x-ip}{2})^{\frac{1}{2}}$

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Now;

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