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Ganezh [65]
3 years ago
5

HELP PLEASE I NEED THIS QUESTION

Mathematics
1 answer:
Lesechka [4]3 years ago
6 0

9514 1404 393

Answer:

  B.  75.8 ft²

Step-by-step explanation:

The height of each triangle can be found using the Pythagorean theorem. The given edge length (7 ft) is the hypotenuse of the triangle, and the base edge length is twice one leg of the triangle.

The height of the triangle on the 2 ft faces is ...

  √(7² -1²) = √48 = 4√3

The height of the triangle on the 8 ft faces is ...

  √(7² -4²) = √33

The areas of the triangular faces are the product of the height and half the base length:

  A = 1/2bh

  2 ft edge triangle area = (1/2)(2 ft)(4√3 ft) = 4√3 ft²

  8 ft edge triangle area = (1/2)(8 ft)(√33 ft) = 4√33 ft²

__

The area of the rectangular base is ...

  A = LW

  A = (8 ft)(2 ft) = 16 ft²

__

The total surface area of the pyramid is the sum of the areas of the triangular faces and the area of the rectangular base.

  2(4√3 +4√33) +16 = 8(2+√3+√33) ≈ 75.813

The total surface area is about 75.8 ft².

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Natalie's group brought in pizza but is buying drinks at the concession stand medium sodas are a dollar and $.25 how many medium
Phantasy [73]

Keywords:

<em>Medium sodas, buy, dollars, divide </em>

For this case we must find the amount of medium sodas that Natalie's group can buy, taking into account that they have 20 dollars and that each medium soda costs 1.25 dollars. To solve, we must divide:

Let "x" be the number of medium sodas you can buy, then:

x = \frac {20} {1.25}\\x = 16

So, Natalie's group can buy 16 medium sodas with 20 dollars

Answer:

16 medium sodas

8 0
3 years ago
A rectangle pool is 7 ft wide, it is 3 times as long as it is wide what’s the dimensions of the pool?
svetoff [14.1K]

The length is 3 times longer than the width (7)

3 x 7 = 21

the length is 21.

To find perimeter, add all sides together:

21 + 21 + 7 + 7 = 42 + 14 = 56

56 ft is your answer

hope this helps

3 0
3 years ago
Read 2 more answers
Help please!!! | DON'T GUESS, please show work
Aleksandr-060686 [28]
For one of the triangular sides, 2.6 x 4 = 10.4 divided by 2 = 5.2
Other triangle; 2.6 x 3 = 7.8 /2 = 3.9
Rectangular side in front; 6.5 x 3 = 19.5
Back; 6.5 x 4 = 26
Base; 6.5 x 2.6 = 16.9
Answer: For the surface area it is 74.6 (SUPER SORRY IF THIS ISNT RIGHT OMG)
5 0
3 years ago
Sarkis wants to draw a triangle with sides measuring 4 ft, 10 ft, and 16 ft. Which is true about Sarkis’s plan?
Liono4ka [1.6K]

Answer:

Sarkis cannot draw a triangle with these side lengths.

Step-by-step explanation:

Sarkis cannot draw a triangle with these side lengths.

5 0
2 years ago
It is known that a cable with a​ cross-sectional area of 0.300.30 sq in. has a capacity to hold 2500 lb. If the capacity of the
vesna_86 [32]

Answer:

0.84 square in

Step-by-step explanation:

Since the capacity of the cable is proportional to its​ cross-sectional area. If a cable that is 0.3 sq in can hold 2500 lb then per square inch it can hold

2500 / 0.3 = 8333.33 lb/in

To old 7000 lb it the cross-sectional area would need to be

7000 / 8333.33 = 0.84 square in

5 0
3 years ago
Read 2 more answers
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