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storchak [24]
3 years ago
12

Anna divided a sheet of paper into 5 equal sections in color 3 of the sections blue what percent of the paper did she color​

Mathematics
1 answer:
e-lub [12.9K]3 years ago
4 0
60/100 is 3/5 so Anna colored 60% of the paper blue
You might be interested in
90 points
yan [13]

Answer:

Pythagorean Theorum is defined in Mathematics by a^2 + b^2 = c^2.

One leg (a) is 5. The other leg (b) is 13.

Let's use Pythagorean Theorum.

5^2 + 13^2 = c^2

5 • 5 = 25

13 • 13 = 169

25 + 169 = 194.

Step-by-step explanation:

Hope this helps

5 0
3 years ago
Read 2 more answers
Find the solution of the given initial value problems in explicit form. Determine the interval where the solutions are defined.
natali 33 [55]

Answer:

The solution of the given initial value problems in explicit form is y=x-x^2-2  and the solutions are defined for all real numbers.

Step-by-step explanation:

The given differential equation is

y'=1-2x

It can be written as

\frac{dy}{dx}=1-2x

Use variable separable method to solve this differential equation.

dy=(1-2x)dx

Integrate both the sides.

\int dy=\int (1-2x)dx

y=x-2(\frac{x^2}{2})+C                  [\because \int x^n=\frac{x^{n+1}}{n+1}]

y=x-x^2+C              ... (1)

It is given that y(1) = -2. Substitute x=1 and y=-2 to find the value of C.

-2=1-(1)^2+C

-2=1-1+C

-2=C

The value of C is -2. Substitute C=-2 in equation (1).

y=x-x^2-2

Therefore the solution of the given initial value problems in explicit form is y=x-x^2-2 .

The solution is quadratic function, so it is defined for all real values.

Therefore the solutions are defined for all real numbers.

4 0
3 years ago
Determine the value of x<br> 10
Luden [163]

Answer:

Also 10

Step-by-step explanation:

This type of triangle has two sides of equal length

3 0
3 years ago
Read 2 more answers
How do I write 500% as a fraction and a decimal
antoniya [11.8K]
Decimal: 5.0
Fraction: 5/1
5 0
3 years ago
Read 2 more answers
One root of the equation x2+6x+q=0 is twice the other root. find q and the roots.
Whitepunk [10]
Suppose one of the roots is a the second is 2a. The factors will be:
(x-a) and (x-2a)
thus
(x-a)(x-2a)=x^2+6x+q
x^2-xa-2ax+2a^2=x^2+6x+q
taking corresponding terms we shall have:
-2ax=6x
solving for a we get
-2a=6
thus
a=-3
but
q=2a^2
substituting the value of a we get:
q=2(-3)^2
q=2*9
q=18
8 0
3 years ago
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