Let say radius is r
<span>its height is h </span>
<span>its lateral area = y </span>
<span>y = 2 pi r h </span>
<span>since the cylinder is inscribed in the sphere </span>
<span>So (2r )^2 + h^2 = 64 </span>
<span>then 4 (r^2) = 64 - h^2 </span>
<span>since y^2 = 4 (pi)^2 r^2 h^2 </span>
<span>then y^2 = (pi)^2 *h^2 * (64 -h^2) </span>
<span>y^2 = 64 (pi)^2 * h^2 - (pi)^2 * h^4 </span>
<span>2 y y' = 128 (pi)^2 * h - 4 (pi)^2 * h^3 </span>
<span>putting y' = 0 </span>
<span>4 (pi)^2 h ( 32 - h^2)=0 </span>
<span>ether h = 0 testing this value (changing of the sign of y' before and after ) y is minimum </span>
<span>or h = 4 sqrt(2) </span>
<span>testing this value (changing of the sign of y' before and after ) y is maximum </span>
<span>So the maximum value of y^2 = (pi)^2 *32 *( 64 - 32) </span>
<span>y^2 = (pi)^2 * (32)^2 </span>
<span>y = 32 (pi) square feet
hope this helps</span>
The volume of the removed portion is 35 cm³.
Step-by-step explanation:
Given,
The length× width× height (L×B×H) of the outer part = 3 cm×3 cm×7 cm
The length× width× height (l×b×h) of the inner part = 2 cm×2 cm×7 cm
To find the volume of the removed portion.
Formula
The volume of the removed portion = volume of outer part - volume of inner part
Volume of rectangular prism = l×b×h
Now,
Volume of outer part = 3×3×7 cm³ = 63 cm³
Volume of inner part = 2×2×7 cm³ = 28 cm³
Hence,
The volume of the removed portion = 63-28 cm³ = 35 cm³
