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3 years ago

A car is a compound machine true or false

Physics

1 answer:

Viktor [21]3 years ago

6 0

True is the answer. I believe

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Kraig pulls a box to the right at an angle of 40 degrees to the horizontal with a force of 30 Newtons. If Kraig pulls the box a

eimsori [14]

Answer:

459.6J

Explanation:

Given parameters:

Angle of pull = 40°

Force applied = 30N

Distance moved = 20m

Unknown:

Work done by Kraig = ?

Solution:

To solve this problem;

Work done = F x dcosФ

d is the distance

F is the force

Ф is the angle given

Work done = 30 x 20cos40° = 459.6J

3 0

3 years ago

Describe in brief the importance of measurement in our daily life?<br>

Volgvan

Measurement tools make our lives safer and better? And they increase the quality and quantity of life. Arguably, the ability to measure calculating

physical properties accurately have tremendous survival value that gives humans adaptive, evolutionary advantages sharpened through many years of natural selection.

6 0

3 years ago

How much power will it take to move a 10 kg mass at an acceleration of 2 m/s² a distance of 10 meters in 5 seconds?

DedPeter [7]

Answer:

100 Watts

Explanation:

<u>These equations are needed to work out the answer:</u>

power= work done/ time taken

work done= force* distance

force= mass* acceleration

force: 10 kg* 2m/s= 20

work done: 20* 10m=200

power: 200/2=100

7 0

3 years ago

A magnetic field is aligned perpendicular to the plane of a circular loop of wire with radius 5.0 cm and 20 turns. The magnetic

Mariana [72]

Answer:

$V = 0.157(-36 e^{-3t} + 1.5)$

$t = 1.24 s$

Part b)

$EMF = 0.136(-36e^{-3t} + 1.5)$

Explanation:

magnetic field due to external source is given as

$B = 12 e^{-3t} + 1.5 t + 6$

area of the loop is given as

$A = \pi r^2$

$A = \pi(0.05)^2$

$A = 7.85 \times 10^{-3} m^2$

Now we have

$\phi = NBAcos0$

$\phi = (20)(12e^{-3t} + 1.5t + 6)(7.85 \times 10^{-3})$

$V = \frac{d\phi}{dt}$

$V = 0.157\frac{d}{dt}(12e^{-3t} + 1.5t + 6)$

$V = 0.157(-36 e^{-3t} + 1.5)$

now we need to find the time at which voltage is 0.1 Volts so we have

$0.1 V = 0.157(-36e^{-3t} + 1.5)$

$t = 1.24 s$

Part b)

If magnetic field is inclined at an angle of 30 degree with the normal of the loop then

$\phi = NBAcos30$

now we know that induced EMF is given as

$EMF = \frac{d\phi}{dt}$

$EMF = NAcos30\frac{dB}{dt}$

$EMF = (20)(7.85 \times 10^{-3})cos30(\frac{d}{dt}(12e^{-3t} + 1.5t + 6))$

$EMF = 0.136(-36e^{-3t} + 1.5)$

7 0

3 years ago

At the same amplitude or volume, which sound would have the highest frequency?

weqwewe [10]

Dog whistle ..................

5 0

3 years ago