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Elena-2011 [213]
3 years ago
6

1.) if the total momentum for a system is the same before and after the collision, we say that momentum is conserved. if momentu

m were conserved, what would be the ratio of the total momentum after the collision to the total momentum before the collision?
2.) if the total kinetic energy for a system is the same before and after the collision, we say that kinetic energy is conserved. if kinetic energy were conserved, what would be the ratio of the total kinetic energy after the collision to the total kinetic energy before the collision?
Physics
1 answer:
gogolik [260]3 years ago
6 0

From the law of the conservation of energy;  the ratio of the total kinetic energy after the collision to the total kinetic energy before the collision must be 1.

<h3>What is momentum?</h3>

The term momentum is the product of mass and velocity. The principle of conservation of linear momentum states that total momentum before collision must be the same as the total momentum after collision thus the  ratio of the total momentum after the collision to the total momentum before the collision must be 1.

Also, from the law of the conservation of energy;  the ratio of the total kinetic energy after the collision to the total kinetic energy before the collision must be 1.

Learn more about momentum:brainly.com/question/24030570

#SPJ1

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What is the force required to propel an object with mass of 12.0 kg at a rate of 27.0 m/s^2
enyata [817]

Newtons second law --> F = ma

So we have mass which = 12.0

And acceleration = 27.0

So the force = (12)(27)

F = 324 N

4 0
4 years ago
Read 2 more answers
Q C Blaise Pascal duplicated Torricelli's barometer using a red Bordeaux wine, of density 984kg/ m³ , as the working liquid (Fig
levacccp [35]

The pressure within Earth's atmosphere is referred to as atmospheric pressure or barometric pressure. 10.701 was the height h of the wine column for normal atmospheric pressure.

<h3>What is Atmospheric pressure?</h3>

The pressure within Earth's atmosphere is referred to as atmospheric pressure or barometric pressure. The definition of the standard atmosphere is 101,325 Pa, or the same as 1013.25 millibars, 760 mm Hg, 29.9212 inches Hg, or 14.696 psi.

The force per unit area that an atmospheric column exerts is known as atmospheric pressure, often known as barometric pressure (that is, the entire body of air above the specified area). A weather indicator is atmospheric pressure. There will typically be clouds, wind, and precipitation when a low-pressure system enters a region. Fair, quiet weather is frequently a result of high pressure systems.

We have the density for the red Bordeaux wine given $\rho=965 \frac{\mathrm{kg}}{\mathrm{m}^3}$, the atmospheric pressure on the Torricelli's barometer is given by:

$$P_{a t m}=\rho g h$$

Solving for the height of wine in the column we have this:

$h=\frac{P_{\text {anm }}}{\rho g}$

And replacing we have:

h=\frac{101300 \mathrm{~Pa}}{965 \frac{\mathrm{kg}}{\mathrm{m}^3 9.81 \frac{\mathrm{m}}{\mathrm{m}^2}}}=10.701 \mathrm{~m}$$

So the height of the red Bordeaux wine would be $\mathrm{h}=10.701 \mathrm{~m}$. A very high value on this case if we compare with the usual values for this variable.

To learn more about Atmospheric pressure refer to:

brainly.com/question/19587559

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6 0
2 years ago
Un camion de 7500 kgg que viaja a 5.0 m/s hacia el este choca con un automovil de 1500 kg que se mueve a 20m/s en dirección 30°
RSB [31]

Responder:

2,1 m / s

53 °

Explicación:

Dado que:

M1 = 7500 kilogramos

V1 = 5 m / s

M2 = 1500 kilogramos

V2 = 20 m / s

Dado que ambos autos se unen después de la colisión (colisión inelástica)

M = M1 + M2 = 1500 + 7500 = 9000

M1V1 - M2V2cos α = MVx

((7500 * 5) - (1500 * 20 * cos30)) / 9000 = Vx

Vx = 1,2799153

Vx = 1,28 m / s

Vy = (M2V2 * sen α) / M

Vy = (- 1500 x 20 * sin30) / 9000

Vy = - 1,667 m / s

Velocidad después de la colisión (V):

V = √Vx² + Vy²

V = raíz cuadrada (1.28 ^ 2 + (-1.667) ^ 2)

V = 2,1017347

V = 2,1 m / s

Dirección:

Tanα = (Vy / Vx)

α = tan ^ -1 (-1,67 / 1,28)

α = 52,531 = 53 °

6 0
3 years ago
What is the significance of the word universal in Newton's law of universal gravitation
mart [117]

Hey I am here to help you.

Newton's law of universal gravation states that every particle attracts every other particles in the universe with a force which is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers

I believe that this answer was helpful.

5 0
3 years ago
The force on a particle is directed along an x axis and given by F = F0(x/x0 - 1) where x is in meters and F is in Newtons. If F
dolphi86 [110]

Answer:

0 j

Explanation:

Work done from point p1 to point p2 is given by

Work = ∫ F.dr

Here we are given

F= F₀ (x/x₀ -1)

F₀=1.2 N

x₀=3.3 m

dr= dx (since distance changes along x-axis only)

We will calculate above integral between given points x=0 and x= 2x₀

Putting value of F  , x₀ and  dr

==> Work = ∫ F₀ (x/x₀ -1)

=∫ 1.2 (x/3.3 - 1) dx

= 1.2 /3.3

=∫(x-3.3)dx

=0.363636∫(x-3.3)dx

=0.363636 [ x²/2 - 3.3x]

we are given lower point value x= 0

upper point value x= 2 x₀ = 2× 3.3 = 6.6

putting lower and upper point values of x

= 0.363636 [ {0²/2-3.3(0)} - { (6.6)² /2 - 3.3 × 6.6}]

=0.363636 [ {0}- {43.56 /2 - 21.78}]

=0.363636 [ -{0}]

=0.363636 [0]

=0 j

i-e work is zero joules or no work !

7 0
4 years ago
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