Answer:
3.11
Step-by-step explanation:
f(4)=f(4-1)+2
=f(3)+2
=f(3-1)+2+2
=f(2)+4
=f(2-1)+2+4
=f(1)+6
=5+6 (f(1)=5)
=11
Answer:
6000 in³
Step-by-step explanation:
To solve this problem, we simply have to find the volume of the shipping container that will be just enough to contain the 20 soda boxes.
To do this, we find the volume of each soda box and multiply it by the total number of soda boxes held by the shipping container.
Volume of the box = L * B * H
L = length = 15 in
B = breadth = 4 in
H = height = 5 in
V = 15 * 4 * 5 = 300 in³
This is the volume of each soda box.
The volume of 20 soda boxes will then be:
V = 20 * 300 = 6000 in³
This is the volume of 20 soda boxes and hence, the minimum size the shipping container can be.
So your present value is 7750. this is what you have now. they give you the intesrest rate which is 4% and how the amount of year is 5.
recall the formula for a compounded continously is
P×e^(r×t)
the answer is 7750×e^(.04×5)
For this case, the first thing we want to do is substitute the value of y = 15 in the equation.
We have then:
15 = -0.08x ^ 2 + 1.6x + 10
Rewriting we have:
0 = -0.08x ^ 2 + 1.6x + 10 - 15
0 = -0.08x ^ 2 + 1.6x - 5
The solutions are:
x1 = 3.876275643042054
x2 = 16.123724356957947
Nearest whole number:
x1 = 4
x2 = 16
were about 15 tons of trout caught in the lake in the years:
1995 + 4 = 1999
1995 + 16 = 2011
Answer:
The year 1999 and the year 2011
