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Vadim26 [7]
3 years ago
8

Given the point D(4,6), what is D' with R-90°

Mathematics
1 answer:
seraphim [82]3 years ago
7 0

Answer:

D'( -6 , 4).

Step-by-step explanation:

In rotation through 90 degrees from the origin

P(x,y) - P'(-y , x)

D(4 , 6) - D'( -6 , 4).

It's simple

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write a fraction less than 1 with a demoninator of 6 that is greater than three fourth what is the answer?
devlian [24]

Answer:

5/6

Step-by-step explanation:

5/6 is less than 1 and greater than 3/4

Think of it like this; there are 4 quarters in a dollar, a quarter is worth 25 cents, so 3/4 =.75

And if you divide 5/6 you get .83, which is greater than .75(3/4)

3 0
3 years ago
The elevation of Sports Authority Field in Denver, Colorado is 5280ft. If this is 275ft higher than seven times the elevation of
Scorpion4ik [409]

Answer:

754.3ft

Solved:

5380 divided by 7 = 754.3ft

-----

3 0
3 years ago
PLEASE HELP! 25 POINTS!!!!! <br><br> list the question number then answer
galben [10]

6. The answer is A. 3 - 3x

7. The answer is C. -30

8.  The answer is B. -11

9. Believe the answer is B. 7xy

10. The answer is A. 48


4 0
2 years ago
Read 2 more answers
0.23 is a whole number?​
Andru [333]

Answer:

0.23 is a fraction and there is no way to represent it as a whole number.

hope it helps :)

Step-by-step explanation:

8 0
2 years ago
Three students A, B, and C are enrolled in the same class. Suppose that A attends class 30 percent of the time, B attends class
Dvinal [7]

Answer:

(a) 0.93

(b) 0.38

Step-by-step explanation:

A attends class 30% of the time, so DO NOT attend 70%

B attends class 50% of the time, so DO NOT attend 50%

C attends class 80% of the time, so DO NOT attend 20%

Writing as probabilities:

P(A) = 0.30 and P(A') = 0.70

P(B) = 0.50 and P(B') = 0.50

P(C) = 0.80 and P(C') = 0.20

(a) the probability that at least one of them will be in class on a particular day

Let's call Q the event of none of them be in class on a particular day

Probability of at least one be in class is the complement of none of them be there, so: 1 - P(Q)

P(Q) = 0.7*0.5*0.2 = 0.07

1 - P(Q) = 1 - 0.07 = 0.93

(b) the probability that exactly one of them will be in class on a particular day?

One of them exactly be in class is

A is B not C not or A not B is C not or A not B not and C is, so

P(A).P(B').P(C') + P(A').P(B).P(C') + P(A').P(B').P(C)

0.3*0.5*0.2 + 0.7*0.5*0.2 + 0.7*0.5*0.8 =

0.03 + 0.07 + 0.28 = 0.38

4 0
2 years ago
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