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3 years ago

Omar buys stuffed animals for $4 each. He sells them for 7 each. What is the percent profit?

1 answer:

7 0

I believe it is 75% because he is selling them for $3 more than what he bought them for and bought them for $4 and 3 is 75% of 4, sorry if i'm wrong

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oksano4ka [1.4K]

option 2

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3 years ago

Read 2 more answers

If Andre sold 16 magazine subscriptions this week, would he reach his goal? Explain your reasoning.

Alenkasestr [34]

Step-by-step explanation:

what's his goal I will give answer in comments after you tell me

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3 years ago

a roll of wallpaper is on sale for $10. write and solve an inequality to determine how many rolls of wallpaper you can.buy and s

ss7ja [257]

Let x be the number of rolls of wallpaper that you can buy to decorate your kitchen. Since each roll costs $10, the total cost for x rolls is 10x. This value should be not be more than $50. The inequality that is best described is
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Solving for x gives an answer of x ≤ 5.

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3 years ago

Use a matrix to solve the system:

Romashka-Z-Leto [24]

Answer:

(2.83 , 1 , 4)

Step-by-step explanation:

$2x+2y-z=4\\4x-2y-2z=2\\3x+3y-4z=-4\\$

Rewrite these equations in matrix form

$\left[\begin{array}{ccc}2&2&-1\\4&-2&-2\\3&3&-4\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right]=\left[\begin{array}{ccc}4\\2\\-4\end{array}\right] \\$

we can write it like this,

$AX=B\\X=A^{-1}B$

so to solve it we need to take the inverse of the 3 x 3 matrix A then multiply it by B.

We get the inverse of matrix A,

$A^{-1}=\left[\begin{array}{ccc}7/15&1/6&-1/5\\1/3&-1/6&0\\3/5&0&-2/5\end{array}\right] \\$

now multiply the matrix with B

$X=A^{-1}B\\\\\left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}7/15&1/6&-1/5\\1/3&-1/6&0\\3/5&0&-2/5\end{array}\right]\left[\begin{array}{ccc}4\\2\\-4\end{array}\right] \\\\\\\left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}2.83\\1\\4\end{array}\right] \\$

4 0

3 years ago

In ΔABC, m∠B = m∠C. The angle bisector of ∠B meets AC at point H and the angle bisector of ∠C meets AB at point K. Prove that BH

solniwko [45]

Answer:

See explanation

Step-by-step explanation:

In ΔABC, m∠B = m∠C.

BH is angle B bisector, then by definition of angle bisector

∠CBH ≅ ∠HBK

m∠CBH = m∠HBK = 1/2m∠B

CK is angle C bisector, then by definition of angle bisector

∠BCK ≅ ∠KCH

m∠BCK = m∠KCH = 1/2m∠C

Since m∠B = m∠C, then

m∠CBH = m∠HBK = 1/2m∠B = 1/2m∠C = m∠BCK = m∠KCH (*)

Consider triangles CBH and BCK. In these triangles,

∠CBH ≅ ∠BCK (from equality (*));
∠HCB ≅ ∠KBC, because m∠B = m∠C;
BC ≅CB by reflexive property.

So, triangles CBH and BCK are congruent by ASA postulate.

Congruent triangles have congruent corresponding sides, hence

BH ≅ CK.

5 0

3 years ago