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Mnenie [13.5K]
3 years ago
8

TRIANGLE CONGRUENCE! PICTURE ADDED. How is QTP congruent to SPT?

Mathematics
1 answer:
shtirl [24]3 years ago
5 0

Answer:

The triangles are congruent because:

  1. QP = ST
  2. angle P = angle T
  3. the side PT is in both triangles

We know when 2 sides of two triangles and the angle between them is congruent, the triangles are congruent.

You might be interested in
280 is divided between Krutika, Natasha & Richard so that Krutika gets twice as much as Natasha, and Natasha gets three time
Tasya [4]

Answer:

Natasha gets 84

Step-by-step explanation:

Here, we want to know how much Natasha gets

Krutika gets 2 times as much as Natasha

If Natasha gets x, Krutika gets 2x

If Natasha gets x, Richard will get x/3 ( 3 times of this is what Natasha gets)

Now let us have a ratio;

K : N : R

2x : x : x/3

Multiply through by 3

6x : 3x : x

To get the amount Natasha gets, we add up all ratio; (6x + 3x + x ) = 10x

Natasha gets 3x of the total ratio

That will be;

3x /10x * 280

= 3/10 * 280

= 84

5 0
3 years ago
"What is the probability that in 10 dice throws, you will throw AT LEAST two ‘3’s on the dice? Assume you’re throwing a single d
dem82 [27]

Answer:

There is a 51.61% probability that in 10 dice throws, you will throw AT LEAST two ‘3’s on the dice.

Step-by-step explanation:

For each throw, there are only two possible outcomes. Either it is a '3', or it is not. This means that we solve this problem using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

There are 6 possible outcomes for the dice. This means that the probability that it is a '3' is \frac{1}{6} = 0.167

There are 10 throws, so n = 10.

Probability of throwing AT LEAST two ‘3’s on the dice?

Either you throw less than two, or you throw at least two. The sum of the probabilities of these events is 1. So

P(X < 2) + P(X \geq 2) = 1

P(X \geq 2) = 1 - P(X < 2).

In which

P(X < 2) = P(X = 0) + P(X = 1).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.167)^{0}.(0.833)^{10} = 0.1609

P(X = 1) = C_{10,1}.(0.167)^{1}.(0.833)^{9} = 0.3225

So

P(X < 2) = P(X = 0) + P(X = 1) = 0.1609 + 0.3225 = 0.4834.

Finally:

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.4839 = 0.5161.

There is a 51.61% probability that in 10 dice throws, you will throw AT LEAST two ‘3’s on the dice.

5 0
3 years ago
3/4(2x-6)-2(1/2x+1)-1+5x
OlgaM077 [116]

Answer:

Distribute:

=(

3

4

)(2x)+(

3

4

)(−6)+(−2)(

1

2

x)+(−2)(1)+−1+5x

=

3

2

x+

−9

2

+−x+−2+−1+5x

Combine Like Terms:

=

3

2

x+

−9

2

+−x+−2+−1+5x

=(

3

2

x+−x+5x)+(

−9

2

+−2+−1)

11

2

x+

−15

2

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Vhat can be concluded about the line represented in the table? Check all that apply.
Tasya [4]

Answer:

(1,9)   7,90

Step-by-step explanation:

4 0
3 years ago
What is the area of trapezoid ABCD ?
Bumek [7]
AD = 5
BC = 15
AB = 5

Area = 1/2(AD + BC)*AB
Area = 1/2(5 + 15)(5)
Area = 1/2(20)(5)
Area = 50
4 0
3 years ago
Read 2 more answers
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