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Mnenie [13.5K]
3 years ago
8

TRIANGLE CONGRUENCE! PICTURE ADDED. How is QTP congruent to SPT?

Mathematics
1 answer:
shtirl [24]3 years ago
5 0

Answer:

The triangles are congruent because:

  1. QP = ST
  2. angle P = angle T
  3. the side PT is in both triangles

We know when 2 sides of two triangles and the angle between them is congruent, the triangles are congruent.

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I NEED THIS ASAP please. can someone please answer this question i put the picture its on Simplify Expressions im giving 15 poin
kakasveta [241]

Answer:

in step 4

Step-by-step explanation:

we have

0.5(-12c+6)-3(c+4)+10(c-5)\\\\step1=-12c(0.5)+6(0.5)-3(c+4)+10(c-5)\\\\=-6c+3-3(c+4)+10(c-5)\\\\

so step 1 is correct

step 2

-6c+3-3(c+4)+10(c-5)\\\\=-6c+3+c(-3)+4(-3)+10(c-5)\\\\=-6c+3-3c-12+10(c-5)

so step 2 is correct

step 3

-6c+3-3c-12+10(c-5)\\\\=-6c+3-3c-12+c(10)-5(10)\\\\=-6c+3-3c-12+10c-50

so step 3 is correct

step 4

-6c+3-3c-12+10c-50\\\\=(-6c-3c+10c)+(3-12-50)\\\\=(-6-3+10)c+(-9-50)\\\\=(-9+10)c-59\\\\=c-59

so step 4 is incorrect

5 0
3 years ago
Jim is trying to improve his speed on the track so he can qualify for the State Championships. As he is running, he goes from 70
kumpel [21]

Answer:

His acceleration is \frac{1}{15} meters per seconds²

Step-by-step explanation:

Acceleration is the rate of change of the speed

The formula of acceleration is a=\frac{v_{f}-v_{i}}{t} , where

  • v_{f} is the final speed
  • v_{i} is the initial speed
  • The unit of the acceleration is meters/second²

∵ Jim goes from 70 meters/minute (beginning speed) to

   106 meters/minute (final speed) in 9 seconds

∴ His initial speed v_{i} = 70 meters/minute

- Change it the meter per second

∵ 1 minute = 60 seconds

∴ \frac{70}{(1)(60)}=\frac{70}{60}=\frac{7}{6}  meters/second

∴ v_{i} = \frac{7}{6}  meters/second

∵ His final speed v_{f} = 106 meters/minute

- Change it the meter per second

∴ \frac{106}{(1)(60)}=\frac{106}{60}=\frac{53}{30}  meters/second

∴ v_{f} = \frac{53}{30}  meters/second

∵ The time of the change of his speed is 9 seconds

∴ t = 9

∵ The formula of acceleration is a=\frac{v_{f}-v_{i}}{t}

- Substitute the values of t, v_{i}  and v_{f} in the formula above

∴  a=\frac{\frac{53}{30}-\frac{7}{6}}{9}=\frac{1}{15}

∴ His acceleration is \frac{1}{15} meters per seconds²

3 0
3 years ago
How old will kirans aunt be when Kiran is 30 years old
Gemiola [76]

Answer

kiran's aunt is 17 years older than Kiran. How old will Kiran's aunt be when Kiran is: 15 years old? 30 years old? years old? How old will Kiran be when his aunt ...

Step-by-step explanation:

4 0
3 years ago
What are the vertex and x-intercepts of the graph of the function given below?
Travka [436]
In order to determine the vertex of this, you can complete the square.  To do that, first set the equation equal to 0, then move the -35 over to the other side by adding.  That gives us x^{2} -2x=35.  Now we can complete the square.  Do this by taking half of the linear term, squaring it, and adding it in to both sides.  Our linear term is 2x.  Half of 2 is 1, and 1 squared is 1.  So we add 1 to both sides, creating something that looks like this: x^{2} -2x+1=35+1.  We will do the math on the right and get 36, and the left will be expressed as the perfect square binomial we created by doing this whole process.  (x-1)^2=36.  Now move the 36 over by subtraction and set it back to equal y and your vertex is apparent.  It is (1, -36).  You find the x-intercepts when y = 0.  That means you need to set your original equation equal to zero and factor it.  The easiest, surest way to do this is to use the quadratic formula.  Doing that gives us x values of 7 and -5.  And you're done!
7 0
2 years ago
Read 2 more answers
Hi could someone just help me with this I'm not sure if i'm doing it correctly.
salantis [7]
Two angles are supplementary when they <span>add up to 180 degrees </span>⇒
m∠1 + m∠2 = 180°
4y + 7 + 9y + 4 = 180
13y + 11 = 180
13y = 180 - 11
13y = 169
y = 169/13
y = 13

m∠2 = 9y + 4 = 9 * 13 + 4 = 121°
4 0
3 years ago
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