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3 years ago

Need help please on this please

Mathematics

1 answer:

dsp733 years ago

3 0

Answer:

A (8,-3)

B (8,1)

C (2,4)

D (2,0)

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Find the distance between the points given. (0,6) and (5,12)

Elan Coil [88]

$d = \sqrt{(x_2 - x_1)^{2} + (y_2 - y_1)^{2}} \\d = \sqrt{(5 - 0)^{2} + (12 - 6)^{2}} \\d = \sqrt{(5)^{2} + (6)^{2}} \\d = \sqrt{25 + 36} \\d = \sqrt{61} \\d = 7.8 \\\\(x - h)^{2} + (y - k)^{2} = r^{2} \\(x - 5)^{2} + (y - 6)^{2} = 7.8^{2} \\(x - 5)^{2} + (y - 6)^{2} = 61 \\(h, k) = (5, 6)$

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3 years ago

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Which expression is equivalent to 1/8x−1/2 ? 1/8(x−1/2) 1/8(x−4) 1/8(x−1/4) −1/8(x−4)

s344n2d4d5 [400]

The correct answer is B

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4 years ago

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Write an equation for the line that contains (6, 15) that is parallel to the line with equation x−2y=−10. Write your equation in

prisoha [69]

Answer:

y=1/2+12

Step-by-step explanation:

first you have to find the slope to the first equation and that is x/2 and then you have to use the point and plug all of that into slope intercept form(y=mx+b)

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3 years ago

Find the error (-8x^2y^2)^2= -64x^4y^4

ExtremeBDS [4]

Answer:

$(-8)^2\neq-64$

Step-by-step explanation:

Using the distributive property to expand, we have

$(-8x^2y^2)^2=(-8)^2(x^2)^2(y^2)^2.$

Squaring each term, we have

$(-8x^2y^2)^2=64x^4y^4.$

The mistake was that $8^2=64,$ not $-64.$ Using the fact that $8^2=64,$ the right answer would be

$\boxed{64x^4y^4}$ .

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2 years ago

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Please help me. i really need this grade

Elodia [21]

So we have to put the value of 1:3 in a ratio

1 : 3
= 3:y

Ask yourself what do I have to multiply one by to get three ( the answer is three)
Because one side is multiplied by three, you have to multiply the right hand side by three to get y
3*3 is 9

Therefore, the y for 3 hours is 9

Then, we have to make another ratio
1:3
= 5:x

Ask yourself what do I have to multiply by one to get five (the answer is five)
So you multiply the other side by five as well
3*5=15

Therefore, the y for five hours is 15

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4 years ago