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Alenkasestr [34]
3 years ago
5

What is 6/10 as hundredths in fraction form

Mathematics
1 answer:
Step2247 [10]3 years ago
7 0
To get in hundredths form you need to multiply both the numerator and denominator by 10. 6×10=60 and 10×10=100
The answer is 60/100
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6 + ( 2 − 3 ( 4 ) ) + 1 /( 5 ) ( 2 ) − 4
tankabanditka [31]

6 + (2 - 3 (4) )+1 / (5) (2) - 4 = -1 /2

<u>Step-by-step explanation:</u>

6 + (2 - 3 (4) )+1 / (5) (2) - 4

Using the BODMAS rule, we can simplify the expression in the following way, like, we have to do the operation inside the brackets first, then division, multiplication, addition and then subtraction.

= 6 + (2 - 3 (4) )+1 / (5) (2) - 4  [operation inside the brackets]

= 6 + (2 - 12) )+1 / (5) (2) - 4  

= 6 + (-10) )+1 / (10) - 4

=   6 + 1 -10 / (10) - 4

=  7 - 10/ 6

= -3 / 6

= -1/2

4 0
3 years ago
Anton will be constructing a segment bisector with a compass and straightedge, while Maxim will be constructing an angle bisecto
Genrish500 [490]

The similarities are;

  • Compass and a straight edge required for both construction
  • Both construction includes a line drawn from the intersection of arcs to bisect a segment or an angle
  • The bases for the construction of both bisector are the ends of segment and the angle to be bisected
  • The width of the compass when drawing intersecting arcs, is more than half the width of the segment or angle being bisected

The differences are;

  • Two points of intersection of arcs are used in the segment bisector while only one is requited in an angle bisector
  • The bisecting line crosses the segment in a segment bisector, while it stops at the vertex of the angle being bisected in an angle bisector

The sources of the above equations are as follows;

The steps to construct a segment bisector are;

  • Place the needle of the compass at one of the ends of the line segment to be bisected
  • Widen the compass so as to extend more than half of the length of the segment to be bisected
  • Draw two arcs, one above, and the other below the line
  • Place the compass needle at the other end and with the same compass width draw arcs that intersects with the arcs drawn in the above step
  • Draw a line segment by placing the ruler on the points of intersection of the arcs above and below the line

The steps to construct an angle bisector are;

  • With the compass needle at the vertex, open the pencil end such that arcs can be drawn on the rays (lines) forming the angle
  • Draw an arc on both lines forming the angle
  • Place the compass needle at one of the intersection points and draw an arc in between the lines forming the angle
  • Repeat the above step with the same compass width from the other intersection point with the rays forming the angle
  • Join the point of intersection of the two arcs to the vertex of the angle to bisect the angle

Therefore, we have;

The similarities are;

  • A compass and a straight edge can be used for both construction
  • A straight line is drawn from the point of intersection of arcs to bisect the segment or the angle
  • The arcs are drawn from the ends of the segment or angle to be bisected
  • The width of the compass is more than half the width of the line or angle when drawing the arcs

The differences are;

  • In a segment bisector, the intersection point is above and below the line, while in an angle bisector only one pair of arcs are drawn to intersect above the line
  • The bisecting line passes through the segment being bisected, while the line stops at the vertex in an angle bisector

Learn more about the construction of segment and angle bisectors here;

brainly.com/question/17335869

brainly.com/question/12028523

7 0
2 years ago
Find the shaded region of the figure below​
lilavasa [31]

Answer:

-x³ + 3x² - 14x + 12

Step-by-step explanation:

Area of outer rectangle = (x² + 3x - 4) * (2x - 3)

      = (x² + 3x - 4) * 2x  + (x² + 3x - 4) * (-3)

     =x²*2x + 3x *2x - 4*2x  + x² *(-3) + 3x *(-3)  - 4*(-3)

     =2x³ + 6x² - 8x - 3x² - 9x + 12

    = 2x³ + <u>6x² - 3x²</u>   <u>- 8x - 9x</u> + 12     {Combine like terms}

    = 2x³ + 3x² - 17x + 12

Area of inner rectangle = (x² - 1)* 3x

                                       = x² *3x - 1*3x

                                       = 3x³ - 3x

Area of shaded region = area of outer rectangle - area of inner rectangle

         = 2x³ + 3x² - 17x + 12 - (3x³ - 3x)

         = 2x³ + 3x² - 17x + 12 -3x³ + 3x

        = 2x³ - 3x³ + 3x² - 17x + 3x + 12

        = -x³ + 3x² - 14x + 12

4 0
3 years ago
What are the names to these quadrilaterals ​
olga_2 [115]

Answer:

The top left one is a pentagon, the lower left is a quadrilateral, the top right is a rhombus, and the bottom left is a parallelogram.

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
What's the lim (x^5-x^3+2)/ (®(x+3)-2)​
igomit [66]

Answer:

send here I answer

Step-by-step explanation:

za r i misa 0 g mail

6 0
3 years ago
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