The maximum value of the objective function is 330
<h3>How to maximize the
objective function?</h3>
The given parameters are:
Max w = 5y₁ + 3y₂
Subject to
y₁ + y₂ ≤ 50
2y₁ + 3y₂ ≤ 60
y₁ , y₂ ≥ 0
Start by plotting the graph of the constraints (see attachment)
From the attached graph, we have:
(y₁ , y₂) = (90, -40)
Substitute (y₁ , y₂) = (90, -40) in w = 5y₁ + 3y₂
w = 5 * 90 - 3 * 40
Evaluate
w = 330
Hence, the maximum value of the function is 330
Read more about objective functions at:
brainly.com/question/26036780
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Step-by-step explanation:
So what are you looking for with that equation?
It’s between 3 and 4 but a little closer to 4
Answer:
12 yd.
Step-by-step explanation:
Answer:
3 71/100 = 3.71
Step-by-step explanation:
To convert this mixed number (fraction) to a decimal just follow these two steps:
Step 1: divide numerator (71) by the denominator (100): 71 ÷ 100 = 0.71
Step 2: add this value to the the integer part: 3 + 0.71 = 3.71. So,
3 71/100 = 3.71