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kherson [118]
3 years ago
15

GOT AN Y INTERCEPT AND GRAPH PROBLEM PLS HELPPPPPP!!! HOPE it's NOT TO HARD TO READDDDDDDDD

Mathematics
1 answer:
Novay_Z [31]3 years ago
4 0

Answer:

1) It has a y-intercept of 4

2) A, the rate of change represents how fast the boys run every hour.

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Which of the following differential equations has the slope field below
Nookie1986 [14]

The differential equation that has the given slope is: dy/dx = -xy.

<h3>How to find the differential equation that models the situation?</h3>

We have to look at the slope, given in the graph of the solution of the differential equation, and represented by dy/dx. From the graph, we have that:

  • In quadrants I and III, in which x and y have the same signal, the differential equation is decreasing, hence the slope is negative.
  • In quadrants II and IV, in which x and y have different signals the differential equation is increasing, hence the slope is positive.

The differential equation that is negative when x and y have the same signals and positive when they do not have is given by the following option:

dy/dx = -xy.

More can be learned about differential equations at brainly.com/question/14423176

#SPJ1

6 0
2 years ago
The coordinates of the midpoint of gh are m(-13/2,-6) and the coordinates of one endpoint are g(-4,1). what is the other endpoin
Alex777 [14]

Applying the midpoint formula, the coordinates of the other endpoint are: (-9, -13).

<h3>How to Apply the Midpoint Formula?</h3>

The midpoint formula, which can be used in determining the coordinates of the midpoint between two endpoints is usually expressed as: M[(x1 + x2)/2, (y1 + y2)/2].

Given the following coordinates:

Midpoint of GH --> m(-13/2,-6) = (x, y)

One endpoint ---> G(-4, 1) = (x1, y1)

The other endpoint ---> (x2, y2)

Plug in the values into the formula used in calculating the midpoint:

m(-13/2,-6) = [(-4 + x2)/2, (1 + y2)/2]

Solve for x2

-13/2 = (-4 + x2)/2

-13/2 × 2 = -4 + x2

-13 = -4 + x2

-13 + 4 = x2

-9 = x2

x2 = -9

Solve for y2

-6 = (1 + y2)/2

2(-6) = 1 + y2

-12 = 1 + y2

-12 - 1 = y2

-13 = y2

y2 = -13

Thus, using the midpoint formula, the coordinates of the other endpoint are: (-9, -13).

Learn more about the midpoint formula on:

brainly.com/question/13115533

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4 0
2 years ago
Find the HEIGHT of the rectangular prism given its surface area is 238 square yards.
o-na [289]

Answer:

Height  = 5

Step-by-step explanation:

7 0
3 years ago
Find the missing value 3/8 equals y over 24 ​
oee [108]

Answer:

Step-by-step explanation:

7 0
3 years ago
Match solutions and differential equations. Note: Each equation may have more than one solution. Select all that apply. (a) 7y''
Nonamiya [84]

Answer:

a-e^x,e^{-x}

b-x^{-2}

c-x^3

Step-by-step explanation:

a.7 y''-7 y =0

Auxillary equation

D^2-1=0

(D-1)(D+1)=0

D=1,-1

Then , the solution of given differential equation

y=e^x,y=e^{-x}

2.7x^2y''+14xy'-14 y=0

Y=y=x^3

y=3x^2

y''=6x

Substitute in the given differential equation

42x^3+42x^3-14x^3\neq 0

Hence, x^3 is not a solution of given differential equation

e^x,e^{-x} are also not a solution of given differential equation.

y=x^{-2}

y'=-2x^{-3}

y''=6x^{-4}

Substitute the values in the differential equation

7x^2(6x^{-4})+14x(-2x^{-3})-14 x^{-2}

=42x^{-2}-28x^{-2}-14x^{-2}=0

Hence, x^{-2} is a solution of given differential equation.

c.7x^2y''-42y=0

y=x^3

y'=3x^2

y''=6x

Substitute the values in the differential equation

42x^3-42x^3=0

Hence, x^3 is a solution of given differential equation.

a-e^x,e^{-x}

b-x^{-2}

c-x^3

6 0
4 years ago
Read 2 more answers
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