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mafiozo [28]
3 years ago
9

100serihttps://brainly.com/question/23752325#

Mathematics
2 answers:
d1i1m1o1n [39]3 years ago
7 0

Answer:

what?

Step-by-step explanation:

Ghella [55]3 years ago
3 0

wdym what you want me to do

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Find the missing side
Step2247 [10]

Answer:

\huge\boxed{\sf x = 8.2}

Step-by-step explanation:

Since it is a right-angled triangle, we will apply Pythagoras Theorem.

<u>Given are:</u>

Base = 16

Perpendicular = x

Hypotenuse = 18

<u>Pythagoras Theorem:</u>

\sf (Hypotenuse)^2=(Base)^2+(Perpendicular)^2

(18)² = (16)² + (x)²

324 = 256 + x²

Subtract 256 to both sides

324 - 256 = x²

68 = x²

Take sqrt on both sides

8.2 = x

x = 8.2

\rule[225]{225}{2}

8 0
2 years ago
Help me solve this -&gt; g(x) = 2x + 3<br><br><br><br> g(7)
Ksivusya [100]

Answer:

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Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
I need help finding the answer to <br> -9 - (-4) =
julia-pushkina [17]
A double negative makes a positive
-9 - (-4) = -9 + 4 = -5
7 0
4 years ago
Read 2 more answers
18 + 18 = what? please! I need this for Homework!!! helllpppp
Marat540 [252]
18+18=36 because 1+1 equals 2(20) and 8+8 equals 16. 20+16=36

4 0
3 years ago
In a study about the relationship between marital status and job level, 8,235 males at a large manufacturing firm reported their
Katena32 [7]

Answer:A)The conditional relative frequency among widowed employees of those widowed working at grade 2 or below= 28/42 = 66.67%


Step-by-step explanation:

In a  two way frequency table, conditional relative frequency is it’s a fraction that tells us how many elements of of a group have a certain characteristic.

Here In a study about the relationship between marital status and job level, 8,235 males at a large manufacturing firm reported their job grade (from 1 to 4, with 4 being the highest) and their marital status.

from the given two way frequency table,

Number of widowed employees at grade 1 =8

Number of widowed employees at grade 2=20

∴ Number of widowed employees at grade 2 or below=8+20=28

And the total widowed employees working =42

Now the conditional relative frequency among widowed employees of those widowed working at grade 2 or below=\frac{\text{Number of widowed employees at grade 2 or below}}{\text{Total widowed employees}}=\frac{28}{42}=0.6667=66.67%

Therefore, the conditional relative frequency among widowed employees of those widowed working at grade 2 or below= 28/42 = 66.67%

3 0
4 years ago
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