Answer:
For complex numbers,
a + bi and a - bi
they have the interesting property that if you add them you get the real number 2a
and if you multiply them , because of the difference of square pattern, you get a^2 - b^2 i^2
But since i^2 = -1, we end up with a real number as a product.
e.g. 6 - 5i and 6 + 5i are conjugates of each other
sum = 6-5i + 6+5i = 12
product = 36 - 25i^2
= 36 -(-25) = 61
Your question is even easier, since the denominator is a monomial instead of a binomial, so we just have to multiply by i/i
Also I believe, according to the answer, that you have a typo, and you meant
(-5+i)/(2i)
= (-5+i)/(2i) *i/i
= (-5i + i^2)/2i^2)
= (-5i +i^2)/-2
= (-5i - 1)/-2
= (1 + 5i)/2 or they way they have it: 1/2 + 5i/2
15x15= 225
15x + 105= 225
15x= 225-105
15x= 120
X=8
X+ (x+1) + (x+2) + (x+3)…etc all the way up too +(x+14)=225
The first five numbers of the set: 8, 9, 10, 11, 12
920 cm squared. Divide S by 2 then multiply to find the value of T. If S = 368 then T = 552, 368 + 552 = 920.
Answer:
C≈59.19
Step-by-step explanation:
I hope this helps! ^^
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