Question

What is the following equation formed when completing the square on Y^2-12y=-27

Answer 1

Answer:y^1=3 ,y^2=9 if im wrong sorry im wrong but hope you get an a

Answer 2

Answer:

$(y -6)^{2} = 9$

Step-by-step explanation:

Given the function:

$y^{2} -12y = -27$

To find the completing the square of the above function, we use the following formula:

$a^2-2ab+b^2=(a-b)^2.$ So we have:

$y^{2} -12y = -27$

$y^2-2\times x\times 6+6^2=-27+6^2\\(y-6)^2=-27+36\\ (y-6)^2=9.$

Hope it can find you well.