3 years ago

Evaluate the expression. | -3|

Mathematics

1 answer:

dexar [7]3 years ago

3 0

the answer is 3 u only need to remove the - sign

You might be interested in

Determine whether or not f is a gradient vector field. if it is, find a function φ such that f = ∇φ. (if the vector field is not

MArishka [77]

$\mathbf f(x,y)=(2x-6y)\,\mathbf i+(-6x+10y-7)\,\mathbf j$

For $\mathbf f$ to be the gradient of some scalar function $\varphi(x,y)$ , we need to find $\varphi$ that satisfies

$\dfrac{\partial \varphi}{\partial x}=2x-6y$
$\dfrac{\partial \varphi}{\partial y}=-6x+10y-7$

From the first PDE, it follows that (upon integrating with respect to $x$ )

$\varphi(x,y)=x^2-6xy+g(y)$

Differentiating with respect to $y$ yields

$\dfrac{\partial\varphi}{\partial y}=-6x+10y-7=-6x+\dfrac{\mathrm dg}{\mathrm dy}$
$\implies\dfrac{\mathrm dg}{\mathrm dy}=10y-7\implies g(y)=5y^2-7y+C$

$\implies\varphi(x,y)=x^2-6xy+5y^2-7y+C$

4 0

4 years ago

What is the image of the point (4,7) after a reflection about the line y = 4.?

lord [1]

Answer:

(4, 1)

Step-by-step explanation:

See attachment courtesy of Desmos.