Answer:
(6x-1)(x-2)
You can always use FOIL to check the answers.
Answer:
Probability that randomly selected 4 persons all have insurance is = 0.1897
Step-by-step explanation:
Given that the probability of having an insurance equals 66%=0.66
Thus
Probability that person A has insurance = 0.66
Probability that person B has insurance = 0.66
Probability that person C has insurance = 0.66
Probability that person D has insurance = 0.66
Probability that randomly selected 4 persons all have insurance is
![P(A)\times P(B)\times P(C)\times P(D)\\\\=0.66\times 0.66\times 0.66\times 0.66=0.1897](https://tex.z-dn.net/?f=P%28A%29%5Ctimes%20P%28B%29%5Ctimes%20P%28C%29%5Ctimes%20P%28D%29%5C%5C%5C%5C%3D0.66%5Ctimes%200.66%5Ctimes%200.66%5Ctimes%200.66%3D0.1897)
Answer:
The mean is 21.12.
Step-by-step explanation:
Binomial probability distribution
Probability of exactly x successes on n repeated trials, with p probability.
The expected value of the binomial distribution is:
![E(X) = np](https://tex.z-dn.net/?f=E%28X%29%20%3D%20np)
In this question:
![n = 48, p = 0.44](https://tex.z-dn.net/?f=n%20%3D%2048%2C%20p%20%3D%200.44)
Mean:
![E(X) = np = 48(0.44) = 21.12](https://tex.z-dn.net/?f=E%28X%29%20%3D%20np%20%3D%2048%280.44%29%20%3D%2021.12)
The mean is 21.12.
Answer:
Point: K, W, T, R, Y, J, H, S
Line: KS,
Line Segment: WR, YH, TJ,
Plane: F, Q
Ray: JS, TK
Angle: KTF, KTR, TJY, TJH, HJS, YJS
Parallel Lines: WR and YH
Perpindicular Lines: KS and WR, KS and WH
Segment Addition Postulate: ?
Step-by-step explanation: