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3 years ago

8

The nurse is preparing to administer filgrastim to a client with leukemia who weighs 60 kg. The prescribed dose is 5 mcg/kg/day.

The available dose is 300 mcg/mL. How many milliliters will the nurse administer?

1 answer:

OlgaM077 [116]3 years ago

7 0

300ml.

60×5=300 so yea, that's ur answer

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Help me please‼️

aksik [14]

Answer:

a.

500x+0.04=y

400x+0.05=y

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3 years ago

Una página de plástico diseñada para guardar cromos puede contener hasta 9 cartas. ¿Cuántas páginas se necesitarán para almacena

adelina 88 [10]

Esto significa que debemos tener 58 páginas de plástico para contener las 517 tarjetas.´

<h3>¿Cuántas páginas se necesitarán para almacenar 517 tarjetas? </h3>

Sabemos que cada página puede almacenar hasta 9 cartas.

Entonces queremos ver cuantos grupos de 9 cartas hay en el conjunto de 517, para ver esto tomamos el cociente entre 517 y 9.

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Y no podemos tener un numero racional, así que debemos redondear al proximo número entero, que es 58.

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8 0

1 year ago

Ignore circled one and work it out please

mash [69]

Answer:

a. $\frac{(x-7)}{x^2+x-30}$

Step-by-step explanation:

$\huge \frac{x^2-3x-28}{(x^2+10x+24)(x-5)} \\\\\huge {=\frac{x^2-7x+4x-28}{(x^2+6x+4x+24)(x-5)}}\\\\\huge {=\frac{x(x-7)+4(x-7)}{\{x(x+6)+4(x+6)\}(x-5)}}\\\\\huge {=\frac{(x-7)(x+4)}{(x+6)(x+4)(x-5)}}\\\\\huge {=\frac{(x-7)}{(x+6)(x-5)}}\\\\\huge {=\frac{(x-7)}{x^2+(6-5)x+6(-5)}}\\\\\huge {=\frac{(x-7)}{x^2+x-30}}$

3 0

3 years ago

Find the perimeter of the polygon round your answer to the nearest tenth.

Volgvan

The correct answer is 39 units.Parameter is the
sum of the lengths of all sides of a polygon.
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3 0

2 years ago

The width of a rectangle is increasing at a rate of 2 cm/sec, while the length increases at 3 cm/sec. At what rate is the area i

lorasvet [3.4K]

Answer:

The area of the rectangle is increasing at a rate of $22\ cm^2/s$ .

Step-by-step explanation:

Given : The width of a rectangle is increasing at a rate of 2 cm/ sec. While the length increases at 3 cm/sec.

To find : At what rate is the area increasing when w = 4 cm and I = 5 cm?

Solution :

The area of the rectangle with length 'l' and width 'w' is given by $A=l w$

Derivative w.r.t 't',

$\frac{dA}{dt}=w\frac{dl}{dt}+l\frac{dw}{dt}$

Now, we have given

$\frac{dl}{dt}=3\ cm/s$

$l=5\ cm$

$\frac{dw}{dt}=2\ cm/s$

$w=4\ cm$

Substitute all the values,

$\frac{dA}{dt}=(4)(3)+(5)(2)$

$\frac{dA}{dt}=12+10$

$\frac{dA}{dt}=22\ cm^2/s$

Therefore, the area of the rectangle is increasing at a rate of $22\ cm^2/s$ .

4 0

3 years ago