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Sav [38]
3 years ago
14

What should be done so that the expression will have a value of 10?

Mathematics
2 answers:
ra1l [238]3 years ago
6 0

Answer:

Naruto usamaki is the greatest hokagey in the leaf village

Thepotemich [5.8K]3 years ago
6 0

Answer:

Add parentheses around 2 + 2.

Step-by-step explanation:

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3 years ago
Solve for p:<br><br> p – 23 = -3<br> A. p = 20<br> B. p = -20<br> C. p = -26<br> D. p = 69
Alekssandra [29.7K]
P-23=-3
+23 +23

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2 years ago
A pair of equations is shown below:
Lana71 [14]
Part A: To solve graphically we have to graph first by plotting the y-int which is -9 & -1. Than use the slops 7/1 & 3/1
part B: (2,5)
4 0
3 years ago
Solve 28 + 7y =91<br><br>Y=.....​
Anna35 [415]

Answer:

y = 9

Step-by-step explanation:

28 + 7y = 91 \\ 7y = 91 - 28 \\ 7y = 63 \\  \frac{7y}{7}  =  \frac{63}{7}  \\ y = 9

8 0
3 years ago
Read 2 more answers
Please Help!!
algol13
When you see questions of this nature, test the individual inequalities and look out for their intersection.

For
y < \frac{2}{3} x
Choose a point in the lower or upper half plane created by the line
y = \frac{2}{3} x
The above line is the one which goes through the origin.

Now testing (1,0) yields,

0 < \frac{2}{3} (1)
That is,

0 < \frac{2}{3}
This statement is true. So we shade the lower half of
y = \frac{2}{3} x

For
y \geqslant - x + 2
We test for the origin because, it is not passing through the origin.

0 \geqslant - (0) + 2
This yields
0 \geqslant 2
This statement is false so we shade the upper half.

The intersection is the region shaded in B. The top right graph
8 0
4 years ago
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