ΔBAC ≅ ΔDAC by ASA congruency
Step-by-step explanation:
Congruency of any triangle can be proved by either of these four criteria. These include
SSS, SAS, ASA, AAS where S= sides and A= Angles
In the given figure ΔBAC & ΔDAC
Since the line, AC is a common angular bisector of ∠BAC and ∠DAC
∴ ∠BAC = ∠DAC ∵ AC is an angular bisector and bisects the ∠BAD into two halves
∠BCA=∠DCA ∵AC is an angular bisector and bisects the ∠DCB into two halves
AC=AC ∵Common side
∴ ΔBAC ≅ ΔDAC ⇒by Angle-Side-Angle (ASA) congruency criterion
Answer:
y=-¹/₃x+5
Step-by-step explanation:
y=ax+b
(0,5) (6,3)
x=0 y=5, x=6 y=3
5=a*0+b
3=a*6+b
5=b
3=6a+b
6a+5=3
6a=-2
a=-¹/₃
y=-¹/₃x+5
Oh, this one lol. ok
you gotta read it like its a book.
4 x s(i picked that variable) which is 4s together
4s+12 (if they said'12 less than' then the 12 gotta be adding.)
then u have to divide it so its going to look like this:
4s+12= blah blah blah
'twice the greater number' means you gotta do this: 2(s+2)
so the problem is this: 4s+12=2(s+2)
now you solved it and the answer will beeeeee s=-4
Answer:
113.04 (6 + g) / 32
Step-by-step explanation:
We know that the total area of a cone is:
A = Pi * r * (r + g), let g be the generatrix.
The radius is half the diameter, therefore, 12/2 = 6 feet.
Replacing:
A = 3.14 * (6) * (6 + g) = 113.04 (6 + g) square feet.
To know the total number of tiles package, we must divide the area of the cone by the area occupied by a package. So:
113.04 (6 + g) / 32
The problem statement does not have a height or the value of the generatrix therefore it is not possible to calculate the number of packages.
The result is 1/3 (-6 + x)
