Answer:
im not sure if this is correct but, i got C
Answer:
<h3>6</h3>
Step-by-step explanation:
Given the expression g(c) = 6c/2, we are to find the value when c = 2
Substitute c = 2 into the expression
g(2) = 6(2)/2
g(2) = 12/2
g(2) = 6
<em>Hence the result when c = 2 is 6</em>
Answer:
x = 4
y = 
Step-by-step explanation:
Ummmm
I'm not sure if this is corrrect but this is what I got
So first you solve 2x+4y=22 to find x
and you get x = 
Then you have to subtitute for 
in 
which you then get y=
After you have to subttitute y= for y in x =
which you get as x=4
Finally you get the answer as:
x = 4
y =
Answer:
2x +2x=90
ZRQ
Step-by-step explanation:
FOR THE FIRST ONE, SUM OF ANGLES IN A TRIANGLE IS 180 AND SINCE WE KNOW ONE ANGLE IS 90° THE REST WOULD ADD UPTO 90°
THE SECOND ONE, JUST FOLLOW THE SEQUENCE OF THE MARKED LINES
for XYZ they went from the unlabeled line to the double marked line to the single marked line. similarly go for ZRQ
Answer:
12 mph
Step-by-step explanation:
The relationship between jogging speed and walking speed means the time it takes to walk 4 miles is the same as the time it takes to jog 8 miles. Then the total travel time (0.75 h) is the time it would take to jog 1+8 = 9 miles. The jogging speed is ...
(9 mi)(.75 h) = 12 mi/h . . . average jogging speed
__
<em>Check</em>
1 mile will take (1 mi)/(12 mi/h) = 1/12 h to jog.
4 miles will take (4 mi)/(6 mi/h) = 4/6 = 8/12 h to walk.
The total travel time is (1/12 +8/12) h = 9/12 h = 3/4 h. (answer checks OK)
_____
<em>Comment on the problem</em>
Olympic race-walking speed is on the order of 7.7 mi/h, so John's walking speed of 6 mi/h should be considered quite a bit faster than normal. The fastest marathon ever run is on the order of a bit more than 12 mi/h, so John's jogging speed is also quite a bit faster than normal. No wonder he got tired.
