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3 years ago

2. 3h – 10 = 35 44 d

Mathematics

2 answers:

Doss [256]3 years ago

8 0

Step-by-step explanation:

3h - 10 = 35 ➡ 3h = 35 + 10 ➡ 3h = 45 ➡h = 15

alisha [4.7K]3 years ago

6 0

I trust that you meant to type

3h – 10 = 35.

If so, see work below.

1. Add 10 to both sides.

3h – 10 + 10 = 35 + 10

3h + 0 = 45

3h = 45

2. Divide both sides of the linear equation by 3 to find h.

3h/3 = 45/3

h = 15

Is h = 15 correct?

Prove:

Let h = 15 in the given equation.

If we get the same answer on both sides of the equation, then we will know that h = 15 is the right answer.

3(15) – 10 = 35

45 - 10 = 35

35 = 35

The fact that 35 = 35 means that our answer for h is 15.

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On Sunday Sheldon bought 3 and 1/2kg of plant food. He used 1 and 2/3kg on his strawberry plants and used 1/4kg for his tomato p

notsponge [240]

The remaining plant food is: 1 7/12 kg

Step-by-step explanation:

Given

Total Plant food = 3 1/2 kg

Plant food used on Strawberry Plants = 1 2/3 kg

Plant food used on tomato Plants = 1/4 kg

We will first calculate the total food plant used and then subtract the used plant food from the total plant food.

So,

$Total\ Plant\ Food\ used=1\frac{2}{3}+\frac{1}{4}\\=\frac{5}{3}+\frac{1}{4}\\=\frac{20+3}{12}\\=\frac{23}{12}$

Now,

$Left\ Food\ Plant=3\frac{1}{2}-\frac{23}{12}\\=\frac{7}{2}-\frac{23}{12}\\=\frac{42-23}{12}\\=\frac{19}{12}\\=1\frac{7}{12}$

The remaining plant food is: 1 7/12 kg

Keywords: Division, Fractions

Learn more about fractions at:

#LearnwithBrainly

7 0

3 years ago

(3-4i)(6i+7)-(2-3i)

Sergeu [11.5K]

Answer:

43-7i

Step-by-step explanation:

We are given the expression:

$\displaystyle \large{(3 - 4i)(6i + 7) - (2 - 3i)}$

First, expand 3-4i in 6i+7. To expand binomial with binomial, first we expand 3 in 6i+7 then expand -4i in 6i+7.

$\displaystyle \large{[(3 \cdot 6i) + (3 \cdot 7) + ( - 4i \cdot 6i) + ( - 4i \cdot 7)]- (2 - 3i)} \\ \displaystyle \large{[18i + 21 - 24 {i}^{2} - 28i]- (2 - 3i)}$

Now combine like terms.

$\displaystyle \large{[ - 10i+ 21 - 24 {i}^{2} ]- (2 - 3i)}$

Imaginary Unit

$\displaystyle \large{i = \sqrt{ - 1} } \\ \displaystyle \large{ {i}^{2} = - 1 }$

Therefore:-

$\displaystyle \large{[ - 10i+ 21 - 24 ( - 1) ]- (2 - 3i)} \\ \displaystyle \large{[ - 10i+ 21 + 24]- (2 - 3i)} \\ \displaystyle \large{[ - 10i+ 45]- (2 - 3i)}$