Answer:
$ 327.08
Step-by-step explanation:
Let x = width of the container,
Then Length of the container = 2x
Let h = height of the container,
volume of the container can be calculated as length × width × height
= 2x × x × h
= 2x² h
Then we can say Volume =
= 2x² h=10
If we simplify inorder to get h
We have h= 5/x²
Then the area= (2L×h) +(2xh)
Where L is lenght
x= wish
h= height
= 2× 2x × h+ x× h
= 4x× 5/x + 2x × 5/x
Area = 30/x
Now, the area of the base = length × width
But from question, for the base costs $20 per square meter. Material for the sides costs $12 per square meter
Then the cost C(x)= 2x²× 20+30/x ×12
C(x)= 40x²+35/x²
If we differenciate wrt x we have
C(x)= 80-360/x²
If we equate C(x)=0the
80=360/x²
x= 1.651
If substitute to C(x)= 40x²+35/x²
C(x) = 40(1.651)² + 35/(1.651)²
We have cost= 327.08
Answer:
What is the help you need
Plz repost clearly
Given that:
5π/3
=5/3×180
=240°
This is in the Quadrant III
The value of cot 5π/3 will be given by:
cost θ=1/tan θ
thus
tan θ
=tan 5π/3
=tan 240
=tan (240-180)
=tan 60
using an equilateral triangle with lengths 2 units
then
tan 60=√3/1
tan 60=√3
hence
tan 240=√3
❇Answer: y=-5x+5
❇Explanation:
First I'll write down the points given:
(-2,15)➡1st point=(x1,y1)
(2,-5)➡ 2nd point=(x2,y2)
(6,-25)➡ 3rd point=(x3,y3)
(10,-45)➡4th point=(x4,y4)
Calculating slope using 1st and 2nd points:
slope= (y2-y1)/(x2-x1)
=(-5-15)/[2-(-2)]
=-20/4
=-5
Calculating slope using 3rd and 4th points:
slope= (y4-y3)/(x4-x3)
=[-45-(-25)]/(10-6)
=-20/4
=-5
Since slope of first two points and last two points are equal, all of these points lie on same line whose equation can be given in slope-intercept form as,
↪y=mx+c {m is slope}
↪y=-5x+c➡Eqn(1)
Let (0,c) be any point cutting y-axis making
y-intercept=c
Lets take 1st point and (0,c) and apply slope formula,
slope=(c-15)/[0-(-2)]
↪-5=(c-15)/2
↪c-15=-10
↪c=15-10
↪c=5
Put value of c in Eqn(1),
↪y=-5x+5
