The probability that detector B goes off is 0.75
The probability of an event is known to be the likelihood or chance for an event to occur.
From the given information let consider:
- A = the time when detector A goes off, and
- B = the time when detector B goes off
Since one or both of them always goes off, then:
∴
Their complements will be zero, i.e.
Similarly, we are given that:
Then;
∴
The set probability for A will be:
P(A) = 1 - P(A')
P(A) = 1 - 0.35
P(A) = 0.65
Finally, the probability that detector B goes off can be computed as:
P(B) = P(A) P(B|A) +P(A') P(B|A')
P(B) = P(A) (1 - P(B|A')) + P(A') (1 - P(B'|A')
![\mathbf{P(B) = P(A) (1-\dfrac{P(A \ and \ B')}{P(A)}) +P(A') (1 - \dfrac{P(A' \ and B')}{P(A')})}](https://tex.z-dn.net/?f=%5Cmathbf%7BP%28B%29%20%3D%20P%28A%29%20%281-%5Cdfrac%7BP%28A%20%5C%20and%20%5C%20B%27%29%7D%7BP%28A%29%7D%29%20%2BP%28A%27%29%20%281%20-%20%5Cdfrac%7BP%28A%27%20%5C%20and%20B%27%29%7D%7BP%28A%27%29%7D%29%7D)
![\mathbf{P(B) = 0.65 (1-\dfrac{0.25}{0.65}) +0.35 (1 - \dfrac{0}{0.35})}](https://tex.z-dn.net/?f=%5Cmathbf%7BP%28B%29%20%3D%200.65%20%281-%5Cdfrac%7B0.25%7D%7B0.65%7D%29%20%2B0.35%20%281%20-%20%5Cdfrac%7B0%7D%7B0.35%7D%29%7D)
P(B) = 0.75
Learn more about the probability of an event here:
brainly.com/question/25839839
The answer is C. I hope that helps
Answer:
1.21. 1.21 is the answer trust me i took the test
Answer:
Unbalanced force
Explanation:
Forces can be balanced and unbalanced.
The force applied to an object in one direction is greater than the force applied in the opposite direction is called unbalanced force. In this type of force, the force in one direction is more than the force acting in opposite direction. As a result, the object will move in the direction where the magnitude of force is more.
Hence, the correct option is (d) "Unbalanced"