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ss7ja [257]
3 years ago
6

Bismuth-210 has a half-life of 5 days. Find

Mathematics
1 answer:
taurus [48]3 years ago
5 0

Answer:

0.78125g

Step-by-step explanation:

Since there are 35 days in 5 weeks, 7 half-lives of Bismuth-210 will take place. To solve for that, you can divide 100g by 2, 7 times or simply: \frac{100}{2^{7}}

\frac{100}{2} =50\\\frac{50}{2} =25\\\frac{25}{2} =12.5\\\frac{12.5}{2} =6.25\\\frac{6.25}{2} =3.125\\\frac{3.125}{2} =1.5625\\\frac{1.5625}{2} =0.78125

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Will give brainliest
pychu [463]

The equation of a hyperbola is  x^{2}/9 - y^{2}/4 = 1

What are the steps to Hyperbola equation ?

To find the equation of hyperbola, the following steps must be taken. You need to identify;

  • The coordinate of the center
  • The coordinate of the vertices
  • The coordinate of the foci

The general equation of a hyperbola can be expressed as

x^{2}/a^{2} - y^{2}/b^{2} = 1

From the graph, we have the following parameters

a = 3

a^{2} = 3^{2} = 9

b = 2

b^{2} = 2^{2} = 4

The equation of a hyperbola can be expressed as

x^{2}/9 - y^{2}/4 = 1

The vertices = V(+/-a,0) = (+/-3,0)

The center = C(0,0)

The focus = F(+/-C, 0)

Where C^{2} = a^{2}  + b^{2}

C = \sqrt{9 + 4}

C = \sqrt{13}

Focus = F(+/- \sqrt{13}, 0)

The general equation for asymptote = +/- b/a X

= +/-2/3X

Therefore, the equation of a hyperbola can be expressed as

x^{2}/9 - y^{2}/4 = 1

Learn more about hyperbola here: brainly.com/question/3405939

#SPJ1

6 0
2 years ago
The waiting times between a subway departure schedule and the arrival of a passenger are uniformly distributed between 00 and 66
Anna71 [15]
<span>You are given the waiting times between a subway departure schedule and the arrival of a passenger that are uniformly distributed between 0 and 6 minutes. You are asked to find the probability that a randomly selected passenger has a waiting time greater than 3.25 minutes.

Le us denote P as the probability that the randomly selected passenger has a waiting time greater than 3.25 minutes.
P = (length of the shaded region) x (height of the shaded region)
P = (6 - 3.25) * (0.167)
P = 2.75 * 0.167
P = 0.40915
P = 0.41</span><span />
7 0
3 years ago
What is the distance between the points (2, 5) and (5,7)?
Svetlanka [38]

Answer:

\sqrt{13}

Step-by-step explanation:

The distance formula that gives the distance between two points is given as:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Plugging in our given points, we get:

d=\sqrt{(5-2)^2+(7-5)^2},\\d=\sqrt{3^2+2^2},\\d=\sqrt{9+4},\\d=\fbox{$\sqrt{13}$}.

6 0
3 years ago
Prepare journal entries
lara31 [8.8K]

Answer:

c

Step-by-step explanation:

4 0
3 years ago
In ΔABC, a = 660 cm, b = 680 cm and c=100 cm. Find the measure of ∠B to the nearest degree.
scoundrel [369]

Answer:

m∠B = 97^{o}.

Step-by-step explanation:

Since the three sides of the triangle are given, then we apply cosine rule.

b^{2} = a^{2} + c^{2} - 2ac Cos B

But, a = 660 cm, b = 680 cm, and c = 100 cm.

So that;

680^{2} = 660^{2} + 100^{2} -2(660 x 100) Cos B

462400 = 435600 + 10000 - 132000 Cos B

462400 = 445600 - 132000 Cos B

132000 Cos B = 445600 - 462400

                        = -16800

Cos B = \frac{-16800}{132000}

         = -0.1273

B = Cos^{-1} -0.1273

  = 97^{o}

Thus, measure of ∠B is 97^{o}.

7 0
3 years ago
Read 2 more answers
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