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likoan [24]
3 years ago
13

Consider the following sample of fat content (in percentage) of randomly selected hot dogs: (a) Assuming that these were selecte

d from a normal population distribution, a 98 % confidence interval for the population mean fat content is (b) Find a 98 % prediction interval for the fat content of a single future hot dog.
Mathematics
2 answers:
klasskru [66]3 years ago
7 0

Answer:

B

Step-by-step explanation:

Greeley [361]3 years ago
4 0

Answer:

B is better option

Step-by-step explanation:

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What is 2h+3 when h=6
erica [24]

Answer:

15

Step-by-step explanation:

After plugging in the 6, multiply 2 and 6 and then add 3. This equals 15.

7 0
3 years ago
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Can you help me find the answer? i cant do it and i will get j<br>​
Tanya [424]

Answer:

a. 10

b. -4

Step-by-step explanation:

For these problems, since we are given the x, we plug it into the expression and solve.

a.

3(4)-2                  [multiply]

12-2                     [subtract]

10

-------------------------------------------------------------------------------------------------------

b.

5(-2)+6                [multiply]

-10+6                   [subtract]

-4

3 0
3 years ago
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Find dyldx.<br> 3. y=2x sin(3x)
vredina [299]

Answer:

\large\boxed{\dfrac{dy}{dx}=2\sin(3x)+6\cos(3x)}

Step-by-step explanation:

\dfrac{dy}{dx}=(2x\sin(3x))'\\\\\text{use}\ \bigg(g(x)\cdot f(x)\bigg)'=g'(c)f(x)+g(x)f'(x)\\\\\text{and}\ \bigg(f(g(x))\bigg)'=f'(g(x))\cdot g'(x)\\\\\dfrac{dy}{dx}=(2x)'(\sin(3x))+(2x)(\sin(3x))'\\\\\dfrac{dy}{dx}=2\sin(3x)+(2x)(\cos(3x)\cdot(3x)')\\\\\dfrac{dy}{dx}=2\sin(3x)+2x\cos(3x)\cdot3\\\\\dfrac{dy}{dx}=2\sin(3x)+6\cos(3x)

6 0
3 years ago
Hi, can you help me answer this question, please, thank you!
frutty [35]

Given:

mean, u = 0

standard deviation σ = 1

Let's determine the following:

(a) Probability of an outcome that is more than -1.26.

Here, we are to find: P(x > -1.26).

Apply the formula:

z=\frac{x^{\prime}-u}{\sigma}

Thus, we have:

\begin{gathered} P(x>-1.26)=\frac{-1.26-0}{1} \\  \\ P(x>-1.26)=\frac{-1.26}{1}=-1.26 \end{gathered}

Using the standard normal table, we have:

NORMSDIST(-1.26) = 0.1038

Therefore, the probability of an outcome that is more than -1.26 is 0.1038

(b) Probability of an outcome that

4 0
1 year ago
PLEASE HELP FOR A BRAINLIEST!!!! Create your own example and explain how to solve Quadratic Equation using Quadratic Formula. Wh
SVETLANKA909090 [29]

Step-by-step explanation:

1. Create your own example and explain how to solve Quadratic Equation using Quadratic Formula.

The quadratic formula is used to solve quadratic equations. It is shown as   x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

A quadratic equation is generally shown in the form of ax^{2} +bx + c = 0

For example, if you saw the equation  7x^{2} + 3x + 20 = 0

7 would be a, 3 would be b, and 20 would be c.

To solve the equation above, you would fill in the quadratic formula as such, x=\dfrac{-3\pm\sqrt{(3)^2-4(7)(20)}}{2(7)}

Then you could solve for x.

2. What part in the Quadratic Formula is the discriminant?

The discriminant is the equation under the square root on the quadratic formula, b^{2} - 4ac

It is tells us whether there are two solutions, one solutions, or no solutions.

3.  How do you know the number of solutions based on the value of the discriminant?

To know the number of solutions based off of the value of the discriminant, you need to plug in your values. Using the example quadratic equation, 7x^{2} + 3x + 20 = 0

We will plug the values into the discriminant.

3^{2} - 4(7)(20) = -551

Now, if the discriminant is positive it has two real solutions. If the discriminant is zero the equation has no real-number solutions. And finally, if the discriminant is negative, the equation has one real solution. Because our discriminant is -551, the example equation has one real solution.

Hope this helps! (Please consider Brainliest)

8 0
3 years ago
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