Answer:
a) π
b) 33.4
Step-by-step explanation:
C = πd
1) substitute 105 for C: 105 = πd
2) plug in approximate value of 3.14 for π: 105 = (3.14) d
3) isolate to solve for d: 105/3.14 = d
4) simplify: 105/3.14 ≈ 33.4
D because you have to distribute the twelve to complete the equation
The question is:
Check whether the function:
y = [cos(2x)]/x
is a solution of
xy' + y = -2sin(2x)
with the initial condition y(π/4) = 0
Answer:
To check if the function y = [cos(2x)]/x is a solution of the differential equation xy' + y = -2sin(2x), we need to substitute the value of y and the value of the derivative of y on the left hand side of the differential equation and see if we obtain the right hand side of the equation.
Let us do that.
y = [cos(2x)]/x
y' = (-1/x²) [cos(2x)] - (2/x) [sin(2x)]
Now,
xy' + y = x{(-1/x²) [cos(2x)] - (2/x) [sin(2x)]} + ([cos(2x)]/x
= (-1/x)cos(2x) - 2sin(2x) + (1/x)cos(2x)
= -2sin(2x)
Which is the right hand side of the differential equation.
Hence, y is a solution to the differential equation.
Answer:55.56
Step-by-step explanation:
Answer: i think itss A???
