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boyakko [2]
2 years ago
12

Question is in the picture, will give brainliest

Mathematics
1 answer:
schepotkina [342]2 years ago
5 0

Answer:

Last option (bottom right)

Step-by-step explanation:

The scientific notation for 0.002 is 2*10^-3 (you move the decimal 3 to the right to get 2)

multiply the number of mustard seeds with this and you get 80. In scientific notation it is 8*10^1 (move the decimal 1 to the left to get 8.0)

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How many pizzas does a restaurant make each night if 25% of the total is equal to 90 pizzas?
TEA [102]
20% of 90 pizzas is 22.5 pizzas
And since you can’t just buy half a pizza it would have to be 23 pizzas :)
5 0
3 years ago
Read 2 more answers
Which point is on the graph of the equation y = 2 x - 5?
Aneli [31]

Answer:

4

Step-by-step explanation:

the correct answer is number 4

if X = 2 ==> 2x -5 = 2(2) -5 = 4 - 5 = -1

4 0
3 years ago
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Someone please help me I’m doing a test-
tamaranim1 [39]

Answer:

c

Step-by-step explanation:

5 0
3 years ago
-5/4-(-1/6) help please
tiny-mole [99]
A way to add fractions that always works is to multiply each numerator by the denominator of the other, then express the sum of products over the product of the denominators.
\dfrac{a}{b}+\dfrac{c}{d}=\dfrac{a}{b}\cdot\dfrac{d}{d}+\dfrac{c}{d}\cdot\dfrac{b}{b}\\\\=\dfrac{ad+bc}{bd}

Here, you have
\dfrac{-5}{4}-\dfrac{-1}{6}=\dfrac{-5\cdot6-(-1)\cdot4}{4\cdot6}=\dfrac{-26}{24}\\\\=\dfrac{-13}{12}=-1\frac{1}{12}

The sum is -1 1/12
3 0
3 years ago
Given that the mass of an average linebacker at Ursinus College is 250 lbs and the radius of a pea is 0.50 cm, calculate the num
Brilliant_brown [7]

Answer:

1.544*10⁹ Linebackers would be required in order to obtain the same density as an alpha particle

Step-by-step explanation:

Assuming that the pea is spherical ( with radius R= 0.5 cm= 0.005 m), then its volume is

V= 4/3π*R³ = 4/3π*R³ = 4/3*π*(0.005 m)³ = 5.236*10⁻⁷ m³

the mass in that volume would be  m= N*L (L= mass of linebackers=250Lbs= 113.398 Kg)

The density of an alpha particle is  ρa= 3.345*10¹⁷ kg/m³ and the density in the pea ρ will be

ρ= m/V

since both should be equal ρ=ρa , then

ρa= m/V =N*L/V → N =ρa*V/L

replacing values

N =ρa*V/L = 3.345*10¹⁷ kg/m³ * 5.236*10⁻⁷ m³ /113.398 Kg  = 1.544*10⁹ Linebackers

N=1.544*10⁹ Linebackers

7 0
3 years ago
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