All categories

3 years ago

2) Kari is flying her kite at the park. She has let

Mathematics

1 answer:

Ket [755]3 years ago

6 0

Answer:

approx 58 yard we can determine it by pithagoras theorem

You might be interested in

twin bothers, collin and cameron get jobs immediately after graduating from college at the age of 22. collin opts for the higher

11111nata11111 [884]

Collin

22 years = 55,000 USD

+15 years

37 years = 2 x 55,000 = 110,000 USD

+15 years

52 years = 2 x 110,000 = 220,000 USD

Cameron

22 years = 35,000 USD

+10 years

32 years = 2 x 35,000 = 70,000 USD

+10 years

42 years = 2 x 70,000 = 140,000 USD

+10 years

52 years = 2 x 140,000 = 280,000 USD

+10 years

62 years = 2 x 280,000 = 560,000 USD

Retirement Salaries

Collin = 220,000 USD

Cameron = 560,000 USD

5 0

3 years ago

16 mm = cm 4 7/8 13/4

Alekssandra [29.7K]

Answer:

1 cm 6mm

Step-by-step explanation:

10mm=1cm

3 0

3 years ago

Will give brainliest

MariettaO [177]

Answer:

7.1

Step-by-step explanation:

If you count how many units are between the library and the park, it is seven units.

6 0

1 year ago

Read 2 more answers

The 5th term in a geometric sequence is 160. The 7th term is 40. What are possible values of the 6th term of the sequence?

omeli [17]

Answer:

C. The 6th term is positive/negative 80

Step-by-step explanation:

Given

Geometric Progression

$T_5 = 160$

$T_7 = 40$

Required

$T_6$

To get the 6th term of the progression, first we need to solve for the first term and the common ratio of the progression;

To solve the common ratio;

Divide the 7th term by the 5th term; This gives

$\frac{T_7}{T_5} = \frac{40}{160}$

Divide the numerator and the denominator of the fraction by 40

$\frac{T_7}{T_5} = \frac{1}{4}$ ----- equation 1

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Where n is the nth term

So,

$T_7 = a r^{6}$

$T_5 = a r^{4}$

Substitute the above expression in equation 1

$\frac{T_7}{T_5} = \frac{1}{4}$ becomes

$\frac{ar^6}{ar^4} = \frac{1}{4}$

$r^2 = \frac{1}{4}$

Square root both sides

$r = \sqrt{\frac{1}{4}}$

r = ± $\frac{1}{2}$

Next, is to solve for the first term;

Using $T_5 = a r^{4}$

By substituting 160 for T5 and ± $\frac{1}{2}$ for r;

We get

$160 = a \frac{1}{2}^{4}$

$160 = a \frac{1}{16}$

Multiply through by 16

$16 * 160 = a \frac{1}{16} * 16$

$16 * 160 = a$

$2560 = a$

Now, we can easily solve for the 6th term

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Here, n = 6;

$T_6 = a r^{6-1}$

$T_6 = a r^5$

$T_6 = 2560 r^5$

r = ± $\frac{1}{2}$

So,

$T_6 = 2560( \frac{1}{2}^5)$ or $T_6 = 2560( \frac{-1}{2}^5)$

$T_6 = 2560( \frac{1}{32})$ or $T_6 = 2560( \frac{-1}{32})$

$T_6 = 80$ or $T_6 = -80$

$T_6 =$ ±80

Hence, the 6th term is positive/negative 80

8 0

2 years ago

Solve the inequality 4t^2 ≤ 9t-2 please show steps and interval notation. thank you!

FromTheMoon [43]

Answer: $t\in [\dfrac{1}{4},2]$

Step-by-step explanation:

Given

Inequality is $4t^2\leq9t-2$

Taking variables one side

$\Rightarrow 4t^2-9t+2\leq0\\\Rightarrow 4t^2-8t-t+2\leq0\\\Rightarrow 4t(t-2)-1(t-2)\leq0\\\Rightarrow (4t-1)(t-2)\leq0$

Using wavy curve method

$t\in [\dfrac{1}{4},2]$

3 0

2 years ago