Aranibar had 35 in his safety box in January. By thanksgiving, he has $2500. What was his savings rate?
2 answers:
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Answer:
1. shifts the graph right 2 units
2. y = -2(x -3)² +7
Step-by-step explanation:
1) Replacing x with x-h in any function shifts the graph h units to the right. Here, you have replaced x with (x-2), so the graph will be shifted 2 units to the right.
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3) The vertex form of the equation of a parabola is ...
y = a(x -h)² +k . . . . . . . . for vertex (h, k) and vertical scale factor 'a'
Here, the vertex is (h, k) = (3, 7), and the parabola opens downward. This tells us the sign of 'a' is negative.
The graph is not so clear that it is easy to read the value of 'a' directly from it, but there are several clues.
The zeros of the above function are found at h±√(k/a). This graph shows the zeros to be located such that √(7/a) is slightly less than 2. This means the magnitude of 'a' will be slightly more than 7/2² = 1.75. The y-intercept of the function is 7-9a. It is less than -7, but probably more than -14. This puts bounds on 'a':
-14 < 7-9a < -7
-21/9 < -a < -14/9 ⇒ -2.33 < -a < -1.56
If we assume that 'a' is an integer value, we have bounded its magnitude as being between 1.75 and 2.33, so a=-2 is a reasonable choice.
The equation of the graph may be ...
y = -2(x -3)² +7
