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Amanda [17]
3 years ago
7

Short Response 6. Are the triangles at the right simílar? Explain.

Mathematics
1 answer:
Taya2010 [7]3 years ago
5 0

Answer:

Yes they are similar because they are both right angles but the one on the right is bigger than the one on the left.

Step-by-step explanation:

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Evan has 2 pieces of wood: one is 90 inches and the other is 72 inches.he wants to cut both pieces of wood into smaller pieces s
QveST [7]

he will have 18 because both of them could be divided by 18 and its the highest number

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3 years ago
If a sentence is defined recursively by f(0)=3 and f(n+1) = f(n) +5 for n ? 0, then f(2) is A) 2 B) 3 C) 5 D) 8
VladimirAG [237]

The recursive formula f(n+1)=f(n)+5 means that the next term in the sequence is 5 more than the previous one.

So, we know that we start from f(0)=3, which means that the next term is

f(1) = f(0)+5 = 3+5 = 8

Similarly,

f(2) = f(1)+5 = 8+5 = 13

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Is the graph increasing or decreasing?<br> A:increasing <br> B:decreasing <br> C:constant
Ann [662]
Looks like the graph is decreasing to me
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3 years ago
HELP! Find the value of sin 0 if tan 0 = 4; 180 &lt; 0&lt; 270
BabaBlast [244]

Hi there! Use the following identities below to help with your problem.

\large \boxed{sin \theta = tan \theta cos \theta} \\  \large \boxed{tan^{2}  \theta + 1 =  {sec}^{2} \theta}

What we know is our tangent value. We are going to use the tan²θ+1 = sec²θ to find the value of cosθ. Substitute tanθ = 4 in the second identity.

\large{ {4}^{2}  + 1 =  {sec}^{2} \theta } \\  \large{16 + 1 =  {sec}^{2} \theta } \\  \large{ {sec}^{2}  \theta = 17}

As we know, sec²θ = 1/cos²θ.

\large \boxed{sec \theta =   \frac{1}{cos \theta} } \\  \large \boxed{ {sec}^{2}  \theta =  \frac{1}{ {cos}^{2}  \theta} }

And thus,

\large{  {cos}^{2}  \theta =  \frac{1}{17}}   \\ \large{cos \theta =  \frac{ \sqrt{1} }{ \sqrt{17} } } \\  \large{cos \theta =  \frac{1}{ \sqrt{17} }  \longrightarrow  \frac{ \sqrt{17} }{17} }

Since the given domain is 180° < θ < 360°. Thus, the cosθ < 0.

\large{cos \theta =   \cancel\frac{ \sqrt{17} }{17} \longrightarrow cos \theta =  -  \frac{ \sqrt{17} }{17}}

Then use the Identity of sinθ = tanθcosθ to find the sinθ.

\large{sin \theta = 4 \times ( -  \frac{ \sqrt{17} }{17}) } \\  \large{sin \theta =  -  \frac{4 \sqrt{17} }{17} }

Answer

  • sinθ = -4sqrt(17)/17 or A choice.
4 0
3 years ago
How many sides does this polygon have ?
Zielflug [23.3K]
A polygon has 3 sides
4 0
3 years ago
Read 2 more answers
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