1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Svetlanka [38]
3 years ago
9

Why is the ruler placement postulate important?

Mathematics
2 answers:
Oksanka [162]3 years ago
3 0

Answer:

ruler placement postulate is important to define relative positioning between points.

Although both A & C are possible, we don't consider a line to have an "origin". A distance can have an origin, so the answer must be A.

k0ka [10]3 years ago
3 0
Answer is A. a distance
You might be interested in
Determine whether the table represents a linear, quadratic, or exponential function?
FrozenT [24]

Answer:

Linear

Step-by-step explanation:

For every step in x, the y values increase by 4 each time, making it a linear function, since the change in y is constant.

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cleft%20%5C%7B%20%7B%7Bx%2By%3D1%7D%20%5Catop%20%7Bx-2y%3D4%7D%7D%20%5Cright.%20%5C%5C%5Clef
brilliants [131]

Answer:

<em>(a) x=2, y=-1</em>

<em>(b)  x=2, y=2</em>

<em>(c)</em> \displaystyle x=\frac{5}{2}, y=\frac{5}{4}

<em>(d) x=-2, y=-7</em>

Step-by-step explanation:

<u>Cramer's Rule</u>

It's a predetermined sequence of steps to solve a system of equations. It's a preferred technique to be implemented in automatic digital solutions because it's easy to structure and generalize.

It uses the concept of determinants, as explained below. Suppose we have a 2x2 system of equations like:

\displaystyle \left \{ {{ax+by=p} \atop {cx+dy=q}} \right.

We call the determinant of the system

\Delta=\begin{vmatrix}a &b \\c  &d \end{vmatrix}

We also define:

\Delta_x=\begin{vmatrix}p &b \\q  &d \end{vmatrix}

And

\Delta_y=\begin{vmatrix}a &p \\c  &q \end{vmatrix}

The solution for x and y is

\displaystyle x=\frac{\Delta_x}{\Delta}

\displaystyle y=\frac{\Delta_y}{\Delta}

(a) The system to solve is

\displaystyle \left \{ {{x+y=1} \atop {x-2y=4}} \right.

Calculating:

\Delta=\begin{vmatrix}1 &1 \\1  &-2 \end{vmatrix}=-2-1=-3

\Delta_x=\begin{vmatrix}1 &1 \\4  &-2 \end{vmatrix}=-2-4=-6

\Delta_y=\begin{vmatrix}1 &1 \\1  &4 \end{vmatrix}=4-3=3

\displaystyle x=\frac{\Delta_x}{\Delta}=\frac{-6}{-3}=2

\displaystyle y=\frac{\Delta_y}{\Delta}=\frac{3}{-3}=-1

The solution is x=2, y=-1

(b) The system to solve is

\displaystyle \left \{ {{4x-y=6} \atop {x-y=0}} \right.

Calculating:

\Delta=\begin{vmatrix}4 &-1 \\1  &-1 \end{vmatrix}=-4+1=-3

\Delta_x=\begin{vmatrix}6 &-1 \\0  &-1 \end{vmatrix}=-6-0=-6

\Delta_y=\begin{vmatrix}4 &6 \\1  &0 \end{vmatrix}=0-6=-6

\displaystyle x=\frac{\Delta_x}{\Delta}=\frac{-6}{-3}=2

\displaystyle y=\frac{\Delta_y}{\Delta}=\frac{-6}{-3}=2

The solution is x=2, y=2

(c) The system to solve is

\displaystyle \left \{ {{-x+2y=0} \atop {x+2y=5}} \right.

Calculating:

\Delta=\begin{vmatrix}-1 &2 \\1  &2 \end{vmatrix}=-2-2=-4

\Delta_x=\begin{vmatrix}0 &2 \\5  &2 \end{vmatrix}=0-10=-10

\Delta_y=\begin{vmatrix}-1 &0 \\1  &5 \end{vmatrix}=-5-0=-5

\displaystyle x=\frac{\Delta_x}{\Delta}=\frac{-10}{-4}=\frac{5}{2}

\displaystyle y=\frac{\Delta_y}{\Delta}=\frac{-5}{-4}=\frac{5}{4}

The solution is

\displaystyle x=\frac{5}{2}, y=\frac{5}{4}

(d) The system to solve is

\displaystyle \left \{ {{6x-y=-5} \atop {4x-2y=6}} \right.

Calculating:

\Delta=\begin{vmatrix}6 &-1 \\4  &-2 \end{vmatrix}=-12+4=-8

\Delta_x=\begin{vmatrix}-5 &-1 \\6  &-2 \end{vmatrix}=10+6=16

\Delta_y=\begin{vmatrix}6 &-5 \\4  &6 \end{vmatrix}=36+20=56

\displaystyle x=\frac{\Delta_x}{\Delta}=\frac{16}{-8}=-2

\displaystyle y=\frac{\Delta_y}{\Delta}=\frac{56}{-8}=-7

The solution is x=-2, y=-7

4 0
3 years ago
What - |3| math evaluate absolute value
EastWind [94]
The answer is -3, because the negative sign is outside of the absolute value. If the problem looked like this |-3|, then the answer would be 3. To clarify, your answer is -3.
7 0
3 years ago
(MATH) (6) ((PHOTO))<br>label is sq yd​
Annette [7]

Answer:

<em>20 sq yd</em>

Step-by-step explanation:

To find the total amount of sq yd's of paint needed, you have to find the area.

The area of a triangle is: A = 1/2 bh

We know:

b = base = 8

h = height = 5

Plug in and solve:

A = 1/2 (8) (5)

A = 1/2 (40)

A = 20

5 0
3 years ago
Please help me thank you in advance!
Gekata [30.6K]

Answer:

x = √6/2

Step-by-step explanation:

Side a = 1.73205 --> √3

Side b = 1.22474 --> √6/2

Side c = 1.22474 --> √6/2

6 0
3 years ago
Other questions:
  • The difference between the squares of two consecutive numbers is 23. what are the two numbers?
    13·1 answer
  • Cheryl drove 4 hours at a constant rate to travel 160 miles. At what rate did she drive? A. 20 mph B. 35 mph C. 40 mph D. 72 mph
    8·2 answers
  • Need help thanksssssssss
    5·1 answer
  • Ahh can someone please help me
    13·1 answer
  • Which angles are vertical to each other ?
    7·2 answers
  • Which ordered pair is a solution to the equation 3x - 3y= 21? (-3, 10) (3, 10) (-3, -10) (3, -10)
    15·2 answers
  • What is 5.74 in radical form
    9·1 answer
  • How do I find the number of solutions for this equation? 6y = 12x + 36
    13·1 answer
  • ive just joined into a class from remote to now hybrid. we are doing how to find out if an ordered pair is a solution to the lin
    5·1 answer
  • A quality control engineer inspects a random sample of 3 batteries from each lot of 24 car batteries that is ready to be shipped
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!