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Brrunno [24]
2 years ago
7

An art class has 33 students. The ratio of boys to girls is 5:6. How many girls are in this

Mathematics
2 answers:
pogonyaev2 years ago
8 0

Answer:

18 girls

Step-by-step explanation:

Because you have to add the 5 and 6 to get 11. And then you divide the total amount of students (33) by the 11 you got earlier which you get a 3 from.Then you multiply the 3 times the number of girls (6) to get 18 girls. And you would multiply the 3 times the 5 if you wanted to find the number of boys in the art class.

Have a most wonderful day!!

lesya692 [45]2 years ago
7 0

Answer:

boys = 15

girls = 18

---

Step-by-step explanation:

g/b = 6/5

g = (6/5)b

g + b = 33

---

g + b = 33

(6/5)b + b = 33

(6/5)b + (5/5)b = 33

(11/5)b = 33

---

b = 33(5/11)

---

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The following function represents the profit P(n), in dollars, that a concert promoter makes by selling tickets for n dollars ea
Gre4nikov [31]
A) zeroes

P(n) = -250 n^2 + 2500n - 5250

Extract common factor:

P(n)= -250 (n^2 - 10n + 21)

Factor (find two numbers that sum -10 and its product is 21)

P(n) = -250(n - 3)(n - 7)

Zeroes ==> n - 3 = 0  or n -7 = 0
Then n = 3 and n = 7 are the zeros.

They rerpesent that if the promoter sells tickets at 3  or 7 dollars the profit is zero.

B) Maximum profit

Completion of squares

n^2 - 10n + 21 = n^2 - 10n + 25 - 4 = (n^2 - 10n+ 25) - 4 = (n - 5)^2 - 4

P(n) = - 250[(n-5)^2 -4] = -250(n-5)^2 + 1000

Maximum ==> - 250 (n - 5)^2 = 0 ==> n = 5 and P(5) = 1000

Maximum profit =1000 at n = 5

C) Axis of symmetry

Vertex = (h,k) when the equation is in the form A(n-h)^2 + k

Comparing A(n-h)^2 + k with - 250(n - 5)^2 + 1000

Vertex = (5, 1000) and the symmetry axis is n = 5.



8 0
3 years ago
How do I do this problem ?
katrin2010 [14]
Y=13 Because a line equals 180. 180-11=169/13=13
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3 0
3 years ago
Maggie is standing on a platform that is 8 feet above the ground. She throws a ball in the air that hits the ground after 2 seco
Paha777 [63]

The equation that offers the best approximation to this result is: h = -16\cdot t^{2}+28\cdot t + 8. (Choice D)

<h3>How to find the free fall formula for a given scenario</h3>

An object experiments a free fall when it is solely accelerated by gravity on the assumption of an <em>uniform</em> acceleration. The formula is described below:

h =h_{o} + v_{o}\cdot t + \frac{1}{2}\cdot g\cdot t^{2} (1)

Where:

  • h_{o} - Initial height, in feet.
  • v_{o} - Initial speed, in feet per second.
  • t - Time, in seconds.
  • g - Gravitational acceleration, in feet per square second.

If we know that t = 2\,s, h_{o} = 8\,ft, h = 0\,ft, g = -32.174\,\frac{ft}{s^{2}}, then the height formula is:

0 = 8 +2\cdot v_{o} - \frac{1}{2}\cdot (32.174)\cdot (2)^{2}

0 = -56.348+2\cdot v_{o}

v_{o} = 28.174\,\frac{ft}{s}

The equation that offers the best approximation to this result is: h = -16\cdot t^{2}+28\cdot t + 8. (Choice D)

To learn more on free fall, we kindly invite to check this verified question: brainly.com/question/13796105

5 0
2 years ago
Find the suface area of this trangular prism.
Talja [164]
The answer will be 37 yd. Hope it help!
5 0
3 years ago
This table gives a few (x, y) pairs of a line in the coordinate plane. What is the x-intercept of the line?
PIT_PIT [208]

Answer:

<em>x=-14</em>

Step-by-step explanation:

The x-intercept of a line is the value of x that makes y=0.

A line can be expressed in its slope-intercept form:

y=mx+b

Once determined the equation of the line, the x-intercept can be calculated by setting y=0 and solving for x.

Let's find the slope of the line.

Suppose we know the line passes through two points A(x1,y1) and B(x2,y2). The slope can be calculated with the equation:

\displaystyle m=\frac{y_2-y_1}{x_2-x_1}

Let's pick the first two points of the table (-94,24) (-74,18). The slope is:

\displaystyle m=\frac{18-24}{-74+94}=\frac{-6}{20}=-\frac{3}{10}

The equation of the line is:

\displaystyle y=-\frac{3}{10}x+b

Now use one of the points to find b, for example (-94,24):

\displaystyle 24=-\frac{3}{10}\cdot (-94)+b

Operating:

\displaystyle 24=\frac{141}{5}+b

Solving:

b=24-\frac{141}{5}=-\frac{21}{5}

The complete equation of the line is:

\displaystyle y=-\frac{3}{10}x-\frac{21}{5}

To find the x-incercept, set y=0 and solve:

\displaystyle 0=-\frac{3}{10}x-\frac{21}{5}

\displaystyle x=\frac{\frac{21}{5}}{-\frac{3}{10}}=-\frac{21}{5}\cdot \frac{10}{3}

x=-14

5 0
3 years ago
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