1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Brrunno [24]
2 years ago
7

An art class has 33 students. The ratio of boys to girls is 5:6. How many girls are in this

Mathematics
2 answers:
pogonyaev2 years ago
8 0

Answer:

18 girls

Step-by-step explanation:

Because you have to add the 5 and 6 to get 11. And then you divide the total amount of students (33) by the 11 you got earlier which you get a 3 from.Then you multiply the 3 times the number of girls (6) to get 18 girls. And you would multiply the 3 times the 5 if you wanted to find the number of boys in the art class.

Have a most wonderful day!!

lesya692 [45]2 years ago
7 0

Answer:

boys = 15

girls = 18

---

Step-by-step explanation:

g/b = 6/5

g = (6/5)b

g + b = 33

---

g + b = 33

(6/5)b + b = 33

(6/5)b + (5/5)b = 33

(11/5)b = 33

---

b = 33(5/11)

---

You might be interested in
I don't know how to do this . Comment bellow to help my please
Lorico [155]
4a. 99m + 81 = 130m. 4b. 40 + 30z = 70z

5a. 24v + 18 = 41v. 5b. 12c + 16 = 28c

6c. 44 + 48v= 92v. 6b. 40 + 12s = 52s.
4 0
3 years ago
Find the area of triangle ABC with vertices A(2,1), B (12,2), C (12,8). Hence, or otherwise find the perpendicular distance from
Lapatulllka [165]
<h2>The area of a triangle is =54 square units</h2><h2>The perpendicular distance from B to AC is = \frac{108}{\sqrt{149} } units</h2>

Step-by-step explanation:

Given a triangle ABC with vertices A(2,1),B(12,2) and C(12,8)

x_1=2,y_1=1,x_2=12,y_2=2,x_3=12 and      y_3=8

The area of a triangle is= \frac{1}{2} [x_1(y_2-y_3) +x_2 (y_3- y_1)+x_3(y_1-y_2)]

=|\frac{1}{2} [2(2-8+12(8-1)+12(1-2)]|

=|-54| = 54 square units

The length of AC = \sqrt{(x_1-x_3)^{2} +(y_1-y_3)^2}

                          = \sqrt{(2-12)^{2} +(1-8)^2}

                         =\sqrt{149} units

Let the perpendicular distance from B to AC be = x

According To Problem

\frac{1}{2} \times  x \times \sqrt{149} = 54

⇔x =\frac{108}{\sqrt{149} } units

Therefore the perpendicular distance from B to AC is = \frac{108}{\sqrt{149} } units

5 0
3 years ago
What is the slope of a line that passes through the origin and the point (-2,1)?
Mazyrski [523]

Answer:

<em>The slope would be</em><u><em> -1/2. </em></u>

Step-by-step explanation:

Since, the midpoint of the segment joining the points P (0, -4) and B (8, 0),

<em> = </em><u><em>( 4, -2 ), </em></u>

Now, the slope of the line passes through the origin and the point ( 4, -2) is,

= <u>-1/2</u>

<h3><u>i think thats the answer</u></h3><h2><u> </u><em><u>HOPE IT HELPS YOU THOUGH</u></em></h2>
8 0
3 years ago
Please help marking brainliest if it's correct and explain​
yarga [219]
Imma take a guess maybe C
4 0
3 years ago
Factor z^2 – 3z – 18. A. (z + 3)(z – 6) B. (z – 3)(z – 6) C. (z + 8)(z – 10) D. (z + 2)(z – 9)
ozzi
Work shown above! Answer would be A!

5 0
3 years ago
Other questions:
  • Do 3/7and7/3 represent the same length on a number line?
    15·1 answer
  • Part of a hundredths grid is shown.
    11·1 answer
  • Select all expressions that represent the area of the given triangle.
    15·1 answer
  • If it usually takes her 30 minutes to drive the 12 miles from her home to her workplace, how long will it take Roxana to drive f
    10·1 answer
  • Please help me with logarithms!
    8·2 answers
  • Need help plz what is a hole
    6·1 answer
  • Which equation is a point slope form equation for line ab?
    9·1 answer
  • Find the y-intercept of the following equation:<br><br> y = 7/2x - 10/7
    13·1 answer
  • Two ships leave port at the same time. One
    10·1 answer
  • Chad is lining up children's and adult bicycles at the bike shop where he works. The number of children's bicycles is 8 less tha
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!