Please help and tell me how to do so!

Please help! Freshman in high-school Algebra 1

Liono4ka [1.6K]

Answer:

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Step-by-step explanation:

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4 0

2 years ago

Sari is teaching her best friend how to factor trinomials with a leading coefficient greater than 1. She starts with the trinomi

Eva8 [605]

Answer:

See explanation

$2x^2+5x+3=(x+1)(2x+3)$

Step-by-step explanation:

1. Make sure that the trinomial is written in the correct order - the trinomial must be written in descending order from highest power to lowest power. In you case, the trinomial must be written as

$2x^2+5x+3$

2. Decide if the three terms have anything in common, called the greatest common factor or GCF. If so, factor out the GCF. Do not forget to include the GCF as part of your final answer.

In your case, coefficients 2, 5 and 3 do not have common factors, so go to the next step.

3. Multiply the leading coefficient and the constant, that is multiply the first and last numbers together:

$2\cdot 3=6$

4. List all of the factors from step 3 and decide which combination of numbers will combine to get the number next to x:

$6=1\cdot 6\\ \\ \bf{6=2\cdot 3}$

5. After choosing the correct pair of numbers, you must give each number a sign so that when they are combined they will equal the number next to x and also multiply to equal the number found in Step 3:

$2+3=5$

6. Rewrite the original problem with four terms by splitting the middle term into the two numbers chosen in step 5:

$2x^2+5x+3=2x^2+2x+3x+3$

7. Now that the problem is written with four terms, you can factor by grouping:

$2x^2 +2x+3x+3=(2x^2+2x)+(3x+3)=2x(x+1)+3(x+1)=(x+1)(2x+3)$

6 0

2 years ago

The port of South Louisiana, located along 54 miles of the Mississippi River between New Orleans and Baton Rouge, is the largest

Ksenya-84 [330]

Answer:

a) 0.7287

b) 0.9663

c) 0.237

d) 3.65 tons of cargo per week or more that will require the port to extend its operating hours.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 4.5 million tons of cargo per week

Standard Deviation, σ = 0 .82 million tons

We are given that the distribution of number of tons of cargo handled per week is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P( port handles less than 5 million tons of cargo per week)

P(x < 5)

$P( x < 5) = P( z < \displaystyle\frac{5 - 4.5}{0.82}) = P(z < 0.609)$

Calculation the value from standard normal z table, we have,

$P(x < 5) =0.7287= 72.87\%$

b) P( port handles 3 or more million tons of cargo per week)

$P(x \geq 3) = P(z \geq \displaystyle\frac{3-4.5}{0.82}) = P(z \geq −1.82926)\\\\P( z \geq −1.82926) = 1 - P(z < -1.829)$

Calculating the value from the standard normal table we have,

$1 - 0.0337 = 0.9663 = 96.63\%\\P( x \geq 3) = 96.63\%$

c)P( port handles between 3 million and 4 million tons of cargo per week)

$P(3 \leq x \leq 4) = P(\displaystyle\frac{3 - 4.5}{0.82} \leq z \leq \displaystyle\frac{4-4.5}{0.82}) = P(-1.829 \leq z \leq -0.609)\\\\= P(z \leq -0.609) - P(z < -1.829)\\= 0.271-0.034 = 0.237= 23.7\%$