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geniusboy [140]
3 years ago
9

Find the equation for the line that passes through the point (4,2) that is parallel to the line with the equation

Mathematics
1 answer:
siniylev [52]3 years ago
8 0

Step-by-step explanation:

if they are parralel it means gradient is the same

finding equation we find another point which is (x,y)

therefore y - 2/ x - 4 should be equal to 2/3.

y - 2 = 2/3(x - 4)

y - 2 = 2/3x - 8/3

y = 2/3x - 8/3 + 2

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Find the derivative of f(x) = 6/x at x = -2. select one: a. 6 b. 3/2 c. -3/2 d. -6
Ivenika [448]
F(X) = 6/X

F(X) = 6 • 1/X

F(X) = 6 • x^-1

F(X) = 6x^-1

F'(X) = 6 • d(x^-1)/dx

F'(X) = 6 • -1x^-1-1

F'(X) = 6 • -1x^-2

F'(X) = -6x^-2

F'(X) = -6/x^2
F'(-2) = -6/(-2)^2
F'(-2) = -6/4
F'(-2) = -3/2

The solution would be C. -3/2.
5 0
2 years ago
Chloe is installing new windows in her house and needs to determine the amount of sealant she will need around the outside edge
Alexus [3.1K]
36 inches is the correct answer 

I Hope This Helps
3 0
3 years ago
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30 yards = how many feet?
mrs_skeptik [129]

30 yards = 90 ft

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3 years ago
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The area of a circular swimming pool is approximately 18 m2. Which is the best estimate of the radius (r)?
DENIUS [597]

Answer:

the radius=9m2

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8 0
2 years ago
usa el teorema de la altura para proponer como se podria construir un segmento cuya longitud sea media proporcional entre dos se
Mrac [35]
Usando el teorema de altura 

El teorema de altura relaciona la altura (h) de un triángulo rectángulo (ver figura) y los catetos de dos triángulos que son semejantes al anterior ABC, al trazar la altura (h) sobre la hipotenusa. De manera que e<span>n todo </span>triángulo rectángulo, la altura (h<span>) relativa a la </span>hipotenusa<span> es la </span>media geométrica<span> de las dos proyecciones de los </span>catetos<span> sobre la </span>hipotenusa<span> (</span>n<span> y </span>m<span>). Es decir, se cumple que:

</span>\frac{n}{h}= \frac{h}{m}

Dado que el problema establece <span>construir un segmento cuya longitud sea media proporcional entre dos segmentos de 4 y 9 cm, entonces, digamos que n = 4cm y m = 9cm tenmos que:

</span>\frac{4}{h}= \frac{h}{9}

De donde:

h= \sqrt{(4)(9)}=\sqrt{36}=6cm

¿Cómo se podria construir si los segmentos son de a cm y b cm?

Si los segmentos son de a y b cm entonces a y b son parámetros que pueden tomar cualquier valor positivo siempre que se cumpla que:

h= \sqrt{ab}

6 0
3 years ago
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