All categories

3 years ago

Find the equation for the line that passes through the point (4,2) that is parallel to the line with the equation

Mathematics

1 answer:

siniylev [52]3 years ago

8 0

Step-by-step explanation:

if they are parralel it means gradient is the same

finding equation we find another point which is (x,y)

therefore y - 2/ x - 4 should be equal to 2/3.

y - 2 = 2/3(x - 4)

y - 2 = 2/3x - 8/3

y = 2/3x - 8/3 + 2

You might be interested in

What should your units on your base area calculations be, and why? How is this different from the units on your volume calculati

horsena [70]

Answer:

For area, square unit is used as the area is calculated using two dimensions length and breadth.

For volume, cubic unit is used as the volume is calculated using three dimensions length, breadth and height.

Step-by-step explanation:

Area refers to the space occupied by a two dimensional flat object in a plane. For area, square unit is used as the area is calculated using two dimensions length and breadth.

Volume is defined as the space occupied by the three-dimensional object. For volume, cubic unit is used as the volume is calculated using three dimensions length, breadth and height.

7 0

3 years ago

A chef cooked 7 kilograms if the guests only ate 3 quaters of the amount he cooked how much did they eat

Oduvanchick [21]

5.25 kilograms.

3 quarters = 3/4

7 divided by 4 is 1.75

1.75x3 is 5.25.

6 0

2 years ago

26 = 3x - 2 - 7x show york work but please try to summarize you're explanation

Delvig [45]

26 = 3x - 2 - 7x
26 + 2 = -4x
28 / -4 = x
x = -7
Best answer me please!

6 0

3 years ago

Write an equivalent expression -3 + 2/3y - 4 - 1/3y

aliina [53]

Answer:

join the y-related together and the others together

ie -7+1/3y

thats the shortest form one can drill down to, so that should be the answer

Step-by-step explanation:

5 0

3 years ago

Boxes of raisins are labeled as containing 22 ounces. Following are the weights, in the ounces, of a sample of 12 boxes. It is r

ZanzabumX [31]

Answer:

A 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].

Step-by-step explanation:

We are given the weights, in the ounces, of a sample of 12 boxes below;

Weights (X): 21.88, 21.76, 22.14, 21.63, 21.81, 22.12, 21.97, 21.57, 21.75, 21.96, 22.20, 21.80.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean weight = $\frac{\sum X}{n}$ = 21.88 ounces

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 0.201 ounces

n = sample of boxes = 12

$\mu$ = population mean weight

Here for constructing a 90% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, 90% confidence interval for the population mean, $\mu$ is ;

P(-1.796 < $t_1_1$ < 1.796) = 0.90 {As the critical value of t at 11 degrees of

freedom are -1.796 & 1.796 with P = 5%}

P(-1.796 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 1.796) = 0.90

P( $-1.796 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.796 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

P( $\bar X-1.796 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.796 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

90% confidence interval for $\mu$ = [ $\bar X-1.796 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+1.796 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $21.88-1.796 \times {\frac{0.201}{\sqrt{12} } }$ , $21.88+1.796 \times {\frac{0.201}{\sqrt{12} } }$ ]

= [21.78, 21.98]

Therefore, a 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].

8 0

3 years ago