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3 years ago

PLEASE HELP

Mathematics

2 answers:

balandron [24]3 years ago

5 0

Answer:

can I answer your question in comment box

tigry1 [53]3 years ago

3 0

Answer:

can I answer your question in comment box

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What is the sign of the product (3) × (−3) × (−2) × (4)?

Free_Kalibri [48]

Answer:

Positive, because the products (3) × (−3) and (−2) × (4) are negative and the product of two negative numbers is positive.

Step-by-step explanation:

Since 1 * -1 = -1, and -1 * -1 = 1, the product of opposite signs produces negative numbers while the product of same signs produces positive numbers. So the product of 1 * 1 * 1 * -1 = -1, while -1 * -1 * -1 * -1 = 1.

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3 years ago

Evaluate csc(-315°).

Maru [420]

Answer:

$\frac{2}{\sqrt{2} } = \sqrt{2}$

Step-by-step explanation:

Notice from the attached image that -315 degrees is the same as 45 degrees.

Recall as well that the csc function is defined as the reciprocal of the sine function: $csc(x)=\frac{1}{sin(x)}$

Then, you need to evaluate $\frac{1}{sin(45)} = 1/\frac{\sqrt{2} }{2} = \frac{2}{\sqrt{2} } =\sqrt{2}$

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3 years ago

What is the radius of 22cm of a circle

algol13

Answer:

11 cm

Step-by-step explanation:

To find radius just divide diameter of 22 by 2. The answer will be 11.

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2 years ago

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A cyclist travels at distance of 400 meters in 120 seconds towards school, calculate his speed. (Show your work)

DochEvi [55]

we know that

The scalar magnitude of the velocity vector is the speed. The speed is equal to

$Speed=\frac{distance}{time}$

in this problem we have

$distance=400\ m \\time=120\ sec$

substitute in the formula

$Speed=\frac{400}{120}$

$Speed=3.5\frac{m}{sec}$

therefore

the answer Part a) is

the speed is equal to $3.5\frac{m}{sec}$

Part b) Find the velocity

we know that

Velocity is a vector quantity; both magnitude and direction are needed to define it

in this problem we have

the magnitude is equal to the speed

$magnitude=3.5\frac{m}{sec}$

$direction=North\ East\ (NE)$

therefore

the answer Part b) is

the velocity is $3.5\frac{m}{sec}\ North\ East\ (NE)$

Part c)

we know that

the acceleration is equal to the formula

$a=\frac{V2-V1}{t2-t1}$

in this problem we have

$V2=0 \\V1=3.5\frac{m}{sec}$

$t2=15\ sec\\t1=0$

substitute in the formula

$a=\frac{0-3.5}{15-0}$

$a=-\frac{3.5}{15}\frac{m}{sec^{2}}$

$a=-\frac{7}{30}\frac{m}{sec^{2}}$

therefore

the answer Part c) is

the acceleration is $-\frac{7}{30}\frac{m}{sec^{2}}$

This is an example of negative acceleration

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3 years ago

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Royce has $15 with him and spends $12 to buy his favorite comics. He has $3 left, which he deposits in the bank. Which number wi

saveliy_v [14]

It is positive. $3 will be entered in Royce's bank

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4 years ago