Answer:
The probability that a randomly selected depth is between 2.25 m and 5.00 m is 0.55.
Step-by-step explanation:
Let the random variable <em>X</em> denote the water depths.
As the variable water depths is continuous variable, the random variable <em>X</em> follows a continuous Uniform distribution with parameters <em>a</em> = 2.00 m and <em>b</em> = 7.00 m.
The probability density function of <em>X</em> is:

Compute the probability that a randomly selected depth is between 2.25 m and 5.00 m as follows:

![=\frac{1}{5.00}\int\limits^{5.00}_{2.25} {1} \, dx\\\\=0.20\times [x]^{5.00}_{2.25} \\\\=0.20\times (5.00-2.25)\\\\=0.55](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B5.00%7D%5Cint%5Climits%5E%7B5.00%7D_%7B2.25%7D%20%7B1%7D%20%5C%2C%20dx%5C%5C%5C%5C%3D0.20%5Ctimes%20%5Bx%5D%5E%7B5.00%7D_%7B2.25%7D%20%5C%5C%5C%5C%3D0.20%5Ctimes%20%285.00-2.25%29%5C%5C%5C%5C%3D0.55)
Thus, the probability that a randomly selected depth is between 2.25 m and 5.00 m is 0.55.
Answer:
- x = 30°
- RS = 30°, SR = TU = 120°, UR = 90°
- ∠P = 45°
- ∠UTS = 60°
Step-by-step explanation:
(a) If RS = x, then the sum of arcs around the circle is ...
x + 4x +4x +3x = 360°
12x = 360°
x = 30°
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(b) Based on the given ratios, the arc measures are computed from x. For example, ST = TU = 4x = 4(30°) = 120°
- RS = 30°
- ST = 120°
- TU = 120°
- UR = 90°
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(c) Angle P is half the difference of arcs TU and RS:
∠P = (TU -RS)/2 = (120° -30°)/2
∠P = 45°
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(d) Inscribed angle UTS is half the measure of the arc it intercepts. Arc RU has the measure (30° +90°) = 120°, so the measure of UTS is ...
∠UTS = 120°/2 = 60°
Answer:
Step-by-step explanation: