Answer:
1 / q^3 = 1 / q^n
n = - 3
Step-by-step explanation:
1/r^-4 = r^4
p^3 * q^2 * p^4 * q^n * r^3 * r^4 = p^7 q ^5 r^7
(p^3 * p^4 *q^2 * r^3 * r^4 ) / ( p^7 * q^5 * r^7) = 1/q^n
(p^7 * q^2 * r^7) / (p^7 * q^5 * r^7) = 1/q^n
q^2 / q^5 = 1/q^n
1 / q^3 = 1 / q^n
Answer:
t = ln(0.5)/-r
Step-by-step explanation:
The decay rate parameter is missing. I will assume a value of 4% per day.
The exponential decay is modeled by the following equation:
A = A0*e^(-r*t)
where A is the mass after t time (in days), A0 is the initial mass and r is the rate (as a decimal).
At half-life A = A0/2, then:
A0/2 = A0*e^(-0.04*t)
0.5 = e^(-0.04*t)
ln(0.5) = -0.04*t
t = ln(0.5)/-0.04
t = 17.33 days
In general the half-life time is:
t = ln(0.5)/-r
Answer:
154cm squared
Step-by-step explanation:
Answer:
333 in^3
Step-by-step explanation:
Circumference = pi *d
27 = pi*d
Replacing d with 2*r ( 2 times the radius)
27 = pi * 2 * r
Divide each side by 2
27/2 = pi *r
13.5 = pi *r
Divide by pi
13.5/ pi = r
We want to find the volume of a sphere
V = 4/3 pi * r^3
V = 4/3 pi (13.5/pi)^3
= 4/3 pi * (13.5)^3 / (pi^3)
4/3 pi/pi^3 * (13.5)^3
4/3 * 1/ pi^2 *2460.375
3280.5 / pi^2
Let pi be approximated by 3.14
380.5/(3.14)^2
332.7214086 in^3
To the nearest in^3
333 in^3
Answer:
b = 87°
Step-by-step explanation:
In order to answer this question, we need to utilise an important angle fact which is <em>angles in a quadrilateral add up to 360° </em>
Using the information we can set up an equation to find the value of b
→ Form equation
63 + 140 + 70 + b = 360
→ Simplify
273 + b = 360
→ Minus 273 from both sides isolate b
b = 87°
