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Licemer1 [7]
3 years ago
15

Can sombody help me with this math question please? and can u guys not send fake links

Mathematics
1 answer:
solniwko [45]3 years ago
3 0
Dont follow the first one to answer this question cause its a hacker it makes you download a thing and it will damage your phone
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25x = 125x + 3<br><br> x = −10<br> x = −9<br> x = −3<br> x = 3
ICE Princess25 [194]

Answer:

x=-9

Step-by-step explanation:

first you make the coefficients equal to each other by doing a common factor which in this case is 5. Then you have to do the variable for each time the common number is repeated which is 5^x * 5^x= 5^(x+3)*5^(x+3)*5^(x+3) This would make it equal to 5^2x=5^(3x+9). Since the non exponents are common factors you can get rid of them and solve for the exponent by doing 2x=3x+9. You solve that equation to get x=-9.

8 0
3 years ago
5. While bird watching, Gabrielle saw 6 robins and 3 blue jays.
Semenov [28]

Answer:

Neither. They both saw the same amount of birds.

Step-by-step explanation:

Gabrielle saw 9 birds, but so did Chase. 6+3 is 9. 3+6 is also 9. The commutative property of addition states that a+b=b+a.

4 0
4 years ago
Which equation represents a linear function?
olga nikolaevna [1]

Answer: Equation 3

Step-by-step explanation:

It does not have any exponents, meaning it's linear

4 0
3 years ago
Read 2 more answers
It’s a new semester! Students are grouped into three clubs, which each has 10, 4 and 5 students. In how many ways can teacher se
ozzi

Here we must see in how many different ways we can select 2 students from the 3 clubs, such that the students <em>do not belong to the same club. </em>We will see that there are 110 different ways in which 2 students from different clubs can be selected.

So there are 3 clubs:

  • Club A, with 10 students.
  • Club B, with 4 students.
  • Club C, with 5 students.

The possible combinations of 2 students from different clubs are

  • Club A with club B
  • Club A with club C
  • Club B with club C.

The number of combinations for each of these is given by the product between the number of students in the club, so we get:

  • Club A with club B: 10*4 = 40
  • Club A with club C: 10*5 = 50
  • Club B with club C. 4*5 = 20

For a total of 40 + 50 + 20 = 110 different combinations.

This means that there are 110 different ways in which 2 students from different clubs can be selected.

If you want to learn more about combination and selections, you can read:

brainly.com/question/251701

6 0
2 years ago
Plz help I don't know what to do
nikdorinn [45]

Answer:

Step-by-step explanation:

length of an arc(s) = θ/360 x 2πr

where θ is the central angle and r is the radius

3 0
3 years ago
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