Question

A marble is selected at random from a jar containing 3 red​ marbles, 4 yellow​ marbles, and 6 green marbles. What is the probability that ​a) the marble is​ red? ​b) the marble is not​ yellow? ​c) the marble is either red or ​green? ​d) the marble is neither red nor ​green?A marble is selected at random from a jar containing 33 red​ marbles, 44 yellow​ marbles, and 66 green marbles. What is the probability that ​a) the marble is​ red? ​b) the marble is not​ yellow? ​c) the marble is either red or ​green? ​d) the marble is neither red nor ​green?

Answer 1

Answer:  a) $\dfrac{3}{13},\ b)\dfrac{9}{13}\ c)\dfrac{9}{13},\ d)\dfrac{4}{13}$

Step-by-step explanation:

Since we have given that

Number of red marbles = 3

Number of yellow marbles = 4

Number of green marbles = 6

Total number of marbles = 3 +4 +6 = 13

​a) the marble is​ red? ​

Probability of getting a red marble = $\dfrac{3}{13}$

b) the marble is not​ yellow?

Probability of not getting yellow = $\dfrac{3+6}{13}=\dfrac{9}{13}$

​c) the marble is either red or ​green?

Probability of getting either red or green = P(red) + P(green) =$\dfrac{3}{13}+\dfrac{6}{13}=\dfrac{9}{13}$

d) the marble is neither red nor ​green?

Probability of getting neither red nor green = P(getting yellow) = $\dfrac{4}{13}$

Hence, a) $\dfrac{3}{13},\ b)\dfrac{9}{13}\ c)\dfrac{9}{13},\ d)\dfrac{4}{13}$