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Explanation:
Statements are numbered; reasons are in italics.
1. ABCD is a parallelogram with AB≅CD and BC≅AD. <em>Given; definition of a parallelogram</em>.
2. Diagonal AC ≅ diagonal CA. <em>Reflexive property of congruence</em>.
3. ΔABC ≅ ΔCDA. <em>SSS congruence postulate</em>.
4. ∠B ≅ ∠D. <em>CPCTC</em>. (Opposite angles B and D are congruent.)
5. Diagonal BD ≅ diagonal DB. <em>Reflexive property of congruence</em>.
6. ΔABD ≅ ΔCDB. <em>SSS congruence postulate</em>.
7. ∠A ≅ ∠C. <em>CPCTC</em>. (Opposite angles A and C are congruent.)
If the points are on the same line they are co linear. when working with coordinates if the all have the same y as in (x,y) they are on the same line for example, (4,5) (2,5) (9,6) are collinear
Multiples of 11 between 1 and 30:
11, 22
So there are 2 numbers that are multiples of 11 in the bin. There are a total of 30 cards, so the probability is written as 2/30. Or we can simplify it to 1/15.
For the next question:
There are a total of 3 + 8 = 11 balls in the bag.
The probability of choosing a red ball is 3/11.
The probability of choosing a green ball is 8/11.
Multiply the three fractions:
3/11 * 3/11 * 8/11 = 72/1331
So the probability is 72/1331.
For the last question:
A standard deck of cards has 52 cards.
There are 4 queens and 4 kings in the deck.
Probability of choosing a queen is 4/52, and the probability of choosing a king AFTER you already chose a queen is 4/51.
Multiply the two fractions:
4/52 * 4/51 = 16/2652
So the probability is 16/2652 or 4/663
Answer:
7/3
Step-by-step explanation:
The distances have the ratio ...
(Q -P) = (2/3)(R -P)
Q = P +(2/3)R -(2/3)P = (2R +P)/3
Qy = (2Ry +Py)/3 = (2·0 +7)/3 = 7/3
